anonymous
  • anonymous
Need explanation pleaase! Find the equation of the tangent line to the given curve at the given point. Can someone please explain?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[y = 1/cosx - 2cosx \]
roadjester
  • roadjester
To find the tangent line, you must first find the derivative.
anonymous
  • anonymous
given point is ( pi/3 , 1) and answer is 3\[3\sqrt{3x}-y+1-\pi \sqrt{3}=0 \]

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roadjester
  • roadjester
Then use the point-slope formula
anonymous
  • anonymous
Can you show me?
roadjester
  • roadjester
I'm sorry, I have to go...I'll be free tomorrow.
experimentX
  • experimentX
find the derivative, put the values, you will get the slope since you have point and slope ... use single point slope formula
anonymous
  • anonymous
Okay thanks:D but the problem is I keep getting the answer wrong.
anonymous
  • anonymous
y = 1/cosx−2cosx y = - sinx/ cox²x + 2 sinx
anonymous
  • anonymous
f (x) = - tanx/ cosx + 2sinx f ( pi/3) = -2√3 + √3 = - √3
anonymous
  • anonymous
Tangent line at ( pi/3 , 1) : y - 1 = -√3 ( x - pi/3) => y = -√3 x + pi/√3
anonymous
  • anonymous
@bobobo Not sure if your post miss some parentheses!

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