NotTim
  • NotTim
Determine resultant: 25N at 10degrees to the horizontal and 30N horizontally.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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NotTim
  • NotTim
relatively simple. again, i ask for the angle only.
NotTim
  • NotTim
|dw:1333533030424:dw|
experimentX
  • experimentX
|dw:1333522316234:dw|

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experimentX
  • experimentX
try using cosine law
NotTim
  • NotTim
but there are no angles hen (10 isnt' actual an angle within the triangle)
experimentX
  • experimentX
it's 170
NotTim
  • NotTim
wut. how?
experimentX
  • experimentX
because 25 is applied 10 degree to horizontal ... and obviously, it makes 10 degree or 180-10 degree with the horizontal
NotTim
  • NotTim
ok...but how do i apply 170 in this triangle|dw:1333533509958:dw|
NotTim
  • NotTim
(im more familiar with that format)
experimentX
  • experimentX
|dw:1333522738607:dw|
NotTim
  • NotTim
Like
NotTim
  • NotTim
|dw:1333533595849:dw|Like I understand how it applies outside, but how do i calculate the angle within?
experimentX
  • experimentX
30N is parallel to horizontal
experimentX
  • experimentX
|dw:1333522901720:dw|
NotTim
  • NotTim
oh. the z,c, f pattern. got it.
NotTim
  • NotTim
what's our next step then, cos law?
experimentX
  • experimentX
yep ... we have all parameters required to calculate
dumbcow
  • dumbcow
|dw:1333525849053:dw| another way of looking at it
dumbcow
  • dumbcow
\[x^{2} = 25^{2}+30^{2}-2(25)(30)\cos 170\]
NotTim
  • NotTim
thank you! i hadnt thought of this
NotTim
  • NotTim
hey guys. I'm having problems figuring out the angle (again!)
NotTim
  • NotTim
I manged to get 5.4 degrees (the closest yet!), while the actual answer is 4.5 degrees.
NotTim
  • NotTim
i did so by using sin-1(30sin170/54.8)
Carniel
  • Carniel
Yea he is correct
NotTim
  • NotTim
what?
NotTim
  • NotTim
@Carniel Wat?
Carniel
  • Carniel
What they all said to you is correct
NotTim
  • NotTim
yeah, but i still got the wrong angle...
Carniel
  • Carniel
How so? Have you tried Tan,Cos, and Sin?
NotTim
  • NotTim
the trig ratios? it only applies to right angle triangles...doesnt it?
Carniel
  • Carniel
Not if I re-call
NotTim
  • NotTim
Sorry if I sound incredulous, but I really do think it applies only to right angle triangles.
Carniel
  • Carniel
Do you have notes? If soo check to make sure.
NotTim
  • NotTim
i dont have the notes specifically on that (its buried in a box somewhere); ill check the internet.
NotTim
  • NotTim
http://wiki.answers.com/Q/Can_trig_ratios_only_be_used_on_right_triangles http://library.thinkquest.org/20991/alg2/trig.html
Carniel
  • Carniel
There you go then =D
NotTim
  • NotTim
but...i can't use it here...(unless i do component method, which im not allowed to)
Carniel
  • Carniel
Which methods do you recall :)?
dumbcow
  • dumbcow
you need to use Law of Sines \[\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\]
NotTim
  • NotTim
yeah. i used that and got 5.4 degrees.
NotTim
  • NotTim
@dumbcow yeah. i used that and got 5.4 degrees.
NotTim
  • NotTim
hello?
dumbcow
  • dumbcow
ok the 5.4 degrees is the angle inside the triangle, they want the angle of resultant vector --> 10 - 5.45 = 4.55
NotTim
  • NotTim
thanks again

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