Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

NotTim

  • 2 years ago

Determine resultant: 25N at 10degrees to the horizontal and 30N horizontally.

  • This Question is Closed
  1. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    relatively simple. again, i ask for the angle only.

  2. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1333533030424:dw|

  3. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1333522316234:dw|

  4. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    try using cosine law

  5. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but there are no angles hen (10 isnt' actual an angle within the triangle)

  6. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it's 170

  7. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wut. how?

  8. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    because 25 is applied 10 degree to horizontal ... and obviously, it makes 10 degree or 180-10 degree with the horizontal

  9. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok...but how do i apply 170 in this triangle|dw:1333533509958:dw|

  10. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (im more familiar with that format)

  11. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1333522738607:dw|

  12. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Like

  13. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1333533595849:dw|Like I understand how it applies outside, but how do i calculate the angle within?

  14. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    30N is parallel to horizontal

  15. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1333522901720:dw|

  16. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh. the z,c, f pattern. got it.

  17. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what's our next step then, cos law?

  18. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yep ... we have all parameters required to calculate

  19. dumbcow
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1333525849053:dw| another way of looking at it

  20. dumbcow
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[x^{2} = 25^{2}+30^{2}-2(25)(30)\cos 170\]

  21. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you! i hadnt thought of this

  22. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hey guys. I'm having problems figuring out the angle (again!)

  23. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I manged to get 5.4 degrees (the closest yet!), while the actual answer is 4.5 degrees.

  24. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i did so by using sin-1(30sin170/54.8)

  25. Carniel
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yea he is correct

  26. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what?

  27. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Carniel Wat?

  28. Carniel
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What they all said to you is correct

  29. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, but i still got the wrong angle...

  30. Carniel
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    How so? Have you tried Tan,Cos, and Sin?

  31. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the trig ratios? it only applies to right angle triangles...doesnt it?

  32. Carniel
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Not if I re-call

  33. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry if I sound incredulous, but I really do think it applies only to right angle triangles.

  34. Carniel
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Do you have notes? If soo check to make sure.

  35. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont have the notes specifically on that (its buried in a box somewhere); ill check the internet.

  36. Carniel
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    There you go then =D

  37. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but...i can't use it here...(unless i do component method, which im not allowed to)

  38. Carniel
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Which methods do you recall :)?

  39. dumbcow
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you need to use Law of Sines \[\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\]

  40. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah. i used that and got 5.4 degrees.

  41. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @dumbcow yeah. i used that and got 5.4 degrees.

  42. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hello?

  43. dumbcow
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok the 5.4 degrees is the angle inside the triangle, they want the angle of resultant vector --> 10 - 5.45 = 4.55

  44. NotTim
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks again

  45. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.