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NotTim
Group Title
Determine resultant: 25N at 10degrees to the horizontal and 30N horizontally.
 2 years ago
 2 years ago
NotTim Group Title
Determine resultant: 25N at 10degrees to the horizontal and 30N horizontally.
 2 years ago
 2 years ago

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NotTim Group TitleBest ResponseYou've already chosen the best response.0
relatively simple. again, i ask for the angle only.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
dw:1333533030424:dw
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
dw:1333522316234:dw
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
try using cosine law
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
but there are no angles hen (10 isnt' actual an angle within the triangle)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
it's 170
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
because 25 is applied 10 degree to horizontal ... and obviously, it makes 10 degree or 18010 degree with the horizontal
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
ok...but how do i apply 170 in this triangledw:1333533509958:dw
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
(im more familiar with that format)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
dw:1333522738607:dw
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
dw:1333533595849:dwLike I understand how it applies outside, but how do i calculate the angle within?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
30N is parallel to horizontal
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
dw:1333522901720:dw
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
oh. the z,c, f pattern. got it.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
what's our next step then, cos law?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
yep ... we have all parameters required to calculate
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.2
dw:1333525849053:dw another way of looking at it
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.2
\[x^{2} = 25^{2}+30^{2}2(25)(30)\cos 170\]
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
thank you! i hadnt thought of this
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
hey guys. I'm having problems figuring out the angle (again!)
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
I manged to get 5.4 degrees (the closest yet!), while the actual answer is 4.5 degrees.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
i did so by using sin1(30sin170/54.8)
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
Yea he is correct
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
@Carniel Wat?
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
What they all said to you is correct
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
yeah, but i still got the wrong angle...
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
How so? Have you tried Tan,Cos, and Sin?
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
the trig ratios? it only applies to right angle triangles...doesnt it?
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
Not if I recall
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Sorry if I sound incredulous, but I really do think it applies only to right angle triangles.
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
Do you have notes? If soo check to make sure.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
i dont have the notes specifically on that (its buried in a box somewhere); ill check the internet.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
http://wiki.answers.com/Q/Can_trig_ratios_only_be_used_on_right_triangles http://library.thinkquest.org/20991/alg2/trig.html
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
There you go then =D
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
but...i can't use it here...(unless i do component method, which im not allowed to)
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
Which methods do you recall :)?
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.2
you need to use Law of Sines \[\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\]
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
yeah. i used that and got 5.4 degrees.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
@dumbcow yeah. i used that and got 5.4 degrees.
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.2
ok the 5.4 degrees is the angle inside the triangle, they want the angle of resultant vector > 10  5.45 = 4.55
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
thanks again
 2 years ago
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