anonymous
  • anonymous
math 50 help please; anyone out there understand word problems well, its dealing with polynomials
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
apoorvk
  • apoorvk
Yes, please post you problems, I am sure someone here can help you out.
lgbasallote
  • lgbasallote
i am kinda good in algebra...might be of service...
anonymous
  • anonymous
three tired hikers camped overnight. all they had to eat was a bag of apples. during the night, one awoke and ate one-third of the apples. later a second awoke and at one-third of the apples that remained. Much later, the third camper awoke and ate one-third of those apples yet remaining after the other two had eaten. when they got up the next morning, eight apples were left. how many apples did they begin with?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

apoorvk
  • apoorvk
let initial no. of apples be x. so after first ate, apples left = x - x/3 = t second one ate 1/3rd of what remained, so, apples left after he had eaten = t - t/3 =(x - x/3) - (x - x/3)/3 = w after the third ate, remaining apples = w-w/3 =[(x - x/3) - (x - x/3)/3] - [(x - x/3) - (x - x/3)/3]/3 simplifies to: 8x/27 so this is the number of apples left finally, which is stated that it equals '8' so, 8x/27 = 8 solve for 'x', and enjoy!! :))
anonymous
  • anonymous
oh my looks very complicated, but thank you, I hope I can figure out what it all means
anonymous
  • anonymous
1 - 1/3 = 2/3 2/3 - 1/3 ( 2/3) = 4/9 4/9 - 1/3 ( 4/9) = 8/27 Thus 8x/ 27 = 8 => x = ...
apoorvk
  • apoorvk
yeah, it just LOOKS complicated, but it isn't at all. Just go through the equations very carefully, and you 'll strike gold!
anonymous
  • anonymous
thank you everyone for your help
anonymous
  • anonymous
can someone please hoelp explain to me how to do x to the fifth power plus one over x plus one? its dividing by a binomial
apoorvk
  • apoorvk
i am not sure what you meant. this?|dw:1333526212290:dw|
anonymous
  • anonymous
yes, thats cool i didnt know you could do that
anonymous
  • anonymous
I have the answer in the book i just have no clue how they got to that
apoorvk
  • apoorvk
you can actually use the equation editor too. :) so I don't understand what you want me to do. solve that or is it already the final answer. because it is in its factorised form right now.
anonymous
  • anonymous
I have to divide it, the answer given in the back of the book is X to the fourth power minus X to the third power plus X to the second power minus X plus one
anonymous
  • anonymous
|dw:1333527076467:dw|
apoorvk
  • apoorvk
\[x^4 - x^4 + x^3 - x^2 +1\] this is a totally different question right?
apoorvk
  • apoorvk
hmm. okay so that is the quotient for that division right? so divide it.
anonymous
  • anonymous
yes|dw:1333527272236:dw| or something like that, but i dont know how they got their answer
apoorvk
  • apoorvk
just divide like you do for any two polynomials. carry on after first step, i know you are thinking this division will not be possible, but try it, its not difficult. i ll post a solution if you are still unable to do it.
anonymous
  • anonymous
I've tried it and have no idea how they got five terms for a binomial
apoorvk
  • apoorvk
okay i ll post one. in fact i thought the same, but it actually was 5 terms in the end!! wait a min.
anonymous
  • anonymous
sorry to bother you but did you forget about me?
apoorvk
  • apoorvk
no no.. the file attachment was creating a problem, there you are!
1 Attachment
anonymous
  • anonymous
Oh wow,okay thank you
anonymous
  • anonymous
|dw:1333532102968:dw| thats as far as i got on this new problem can you please help me finish it?
anonymous
  • anonymous
ok, my mouse is screwed so I can't draw properly so I can only type out where you went wrong. so for the x^6 + 7x^3 u should really put brackets around the whole term (x^6 + 7x^3) now you can minus it. so -13x^3 - 7x^3 will be -20x^3 not 6. The next number that will be written on top next to x^3 will be -20 because x^3 goes into -20x^3 -20 times.
anonymous
  • anonymous
the answer in the back of the book is X to the third power plus 6
anonymous
  • anonymous
yes because I have not finished it, and only pointed out ur mistake. Please attempt to finish the question urself but if u are still having trouble and desperately need it, I will be post up the solution.
anonymous
  • anonymous
yes can you please walk me though it? i dont understand these very well
anonymous
  • anonymous
|dw:1333534657643:dw|
anonymous
  • anonymous
sorry, it takes too long to draw. let me see if i can find a way to type it out.
anonymous
  • anonymous
and please give me a medal for my efforts.
anonymous
  • anonymous
Ok i've got that but im not seeing the next step and how the answer will result in being X to the third minus 6
anonymous
  • anonymous
I think i typed plus six before but its minus six
anonymous
  • anonymous
ok i'm working on it, just wait.
anonymous
  • anonymous
take your time i still have two essays to write before noon so ill be here a while
anonymous
  • anonymous
hey does the attachment work?
1 Attachment
anonymous
  • anonymous
ok it should work, and if u have any problems feel free to ask. I have also gotten the same answer as u stated so it is clearly correct. Please give me a medal for my efforts.
anonymous
  • anonymous
it works
anonymous
  • anonymous
I gave you a medal when we started, can i give two?
anonymous
  • anonymous
i think u can?
anonymous
  • anonymous
i click around and see what i can do for you, thank you
anonymous
  • anonymous
ur welcome and can we be friends tiffany?
anonymous
  • anonymous
okay i became your fan, is that how the friend thing works?
anonymous
  • anonymous
yep, but that's more like a fan, but can we chat?
anonymous
  • anonymous
like this or you mean on like a face page book tweet thing?
anonymous
  • anonymous
I'll send u a msg.

Looking for something else?

Not the answer you are looking for? Search for more explanations.