Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

hoseinBest ResponseYou've already chosen the best response.0
can explain how this two sides are equal?\[\cos \theta da=r^2d \Omega\]
 2 years ago

hoseinBest ResponseYou've already chosen the best response.0
where da is surface element in spherical coordinate & omeg is solid angle
 2 years ago

JamesJBest ResponseYou've already chosen the best response.0
It looks wrong. If you integrate over the entire sphere, the right hand side is \[ 4 \pi r^2 \] but the left hand side is \[ 8 \pi r^2 \]
 2 years ago

hoseinBest ResponseYou've already chosen the best response.0
it's in classical electrodynamics (by Jackson)page28
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
I think this is the same formula we are finding in figure 4.2.4 on this page http://ocw.mit.edu/courses/physics/802scphysicsiielectricityandmagnetismfall2010/conductorsandinsulatorsconductorsasshields/MIT8_02SC_notes9.pdf though the area is not represented as a differential here. I trust that James' math is right though, so that must have some change in the problem.
 2 years ago

quarkineBest ResponseYou've already chosen the best response.0
r square* d(sigma) = r*d(theta) *r*d(phi) =projection of area element=dA cos(theta) ....in azimuthal coordinates..dw:1334694350771:dw
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.