anonymous
  • anonymous
Y=-X^2+14X-49 Find the -X INTERCEPT and the coordinates of the vertex of the parabola
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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lgbasallote
  • lgbasallote
x intercept is the value of x when y = 0..so set y to zero then solve for x...the vertices i forgot @dpaInc may know though
anonymous
  • anonymous
for the vertice, get it in this form by completing the square: 4a(y-k) = (x-h)^2 where (h, k) is your vertex.
anonymous
  • anonymous
there's actually another way of getting the vertex but I can't recall it. it went something like b/2a ?... sound familiar?

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anonymous
  • anonymous
nah
anonymous
  • anonymous
??
lgbasallote
  • lgbasallote
sounds like quadratic formula @dpaInc =))
anonymous
  • anonymous
The x-coordinate for the vertex of the parabola is x=-b/2a
anonymous
  • anonymous
that's it....
anonymous
  • anonymous
And then plug in to solve for the y-coordinate.
anonymous
  • anonymous
where dhe go?
anonymous
  • anonymous
I think he got it. :D
dumbcow
  • dumbcow
factor and set equal to 0 --> -(x-7)^2 = 0 x = 7
anonymous
  • anonymous
also i think i have a formula for y coord of vertex from a, b, c y = c - (b^2)/4a
anonymous
  • anonymous
it sounds like it's gonna be way easier if you just chug the value of the x-coordinate into the equation. :)
anonymous
  • anonymous
yeah lol
anonymous
  • anonymous
just threw that in there for the sake of it
anonymous
  • anonymous
but that's a good answer still..
anonymous
  • anonymous
Notice that \[y= -x^2+14x-49 =- (x^2 -14 x +49)=-(x-7)^2 \] So the x-intercept is x=7 and the vertex is (-7,0)

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