anonymous
  • anonymous
Determine the quadratic equation for the parabola: range: {y:y ≤ 9}; x-intercepts: -2 and 4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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saifoo.khan
  • saifoo.khan
x = -2 x = 4 (x+2)(x-4) = 0 Solve.
anonymous
  • anonymous
i have to chose from these f(x) = x2 - 2x + 8 f(x) = x2 + 2x - 8 f(x) = -x2 + 2x + 8 f(x) = -x2 - 2x + 8
saifoo.khan
  • saifoo.khan
You may solve this using FOIL and you will get the answer, (x+2)(x-4) = 0

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More answers

anonymous
  • anonymous
thankyou
anonymous
  • anonymous
@saifoo.khan (x+2)(x-4) = 0 is not a quadratic equation for a parabola...
anonymous
  • anonymous
it will only give you the x intercepts of the parabola
saifoo.khan
  • saifoo.khan
@anonymoustwo44 , how? i never said (x+2)(x-4) = 0 is the equation. i him to solve it. (x+2)(x-4) = 0 x^2 -2x - 8 = 0 This will be it.
anonymous
  • anonymous
x^2 -2x - 8 = 0 is not the answer. its y=x^2-2x-8
saifoo.khan
  • saifoo.khan
It's the same thing.. Just the way of representation is different.
anonymous
  • anonymous
then try to graph an x^2-2x-8=0
saifoo.khan
  • saifoo.khan
But still, the answer you gave to the asker was still wrong.
anonymous
  • anonymous
and so are you
saifoo.khan
  • saifoo.khan
Mine was better than yours. hehe.
saifoo.khan
  • saifoo.khan
Atleast mine dosnt have sign mistakes.
anonymous
  • anonymous
but the fact that you set it to zero
anonymous
  • anonymous
anyways
saifoo.khan
  • saifoo.khan
It's the same thing man. Just the different way of representation.
saifoo.khan
  • saifoo.khan
It will give us the same answer.
anonymous
  • anonymous
ok sorry if I've been a bit harsh :D
saifoo.khan
  • saifoo.khan
Me too! :D

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