anonymous
  • anonymous
What is the distance between the zoo and the library? a. 100 feet b. 300 feet c. 600 feet d. 900 feet
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
distance from helicopter to zoo we'll write with X since we have angle 60^0 we can use sin x to get X ... so we have.. \[\LARGE \sin \theta =\frac{300\sqrt3}{x}\] \[\LARGE \sin60^{\circ}=\frac{300\sqrt3}{x}\] since \[\LARGE \sin60^{\circ}=\frac{\sqrt3}{2}\] we have... \[\LARGE \frac{\sqrt3}{2}=\frac{300\sqrt3}{x}\] now use cross multiply and you should get X... \[\LARGE x=600\] now use pythagoras theorem to find distance from G to Zoo \[\LARGE a^2+b^2=c^2\] substitute and tell me where are you stucked (if you get stucked somewhere) ... Good Luck !
anonymous
  • anonymous
or wait... you don't have to do that... we have angle 30^0 we can find distance from point G till to Zoo.... just use Tangent.. do you know how it goes ??

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
till library ... my mistake ;)
anonymous
  • anonymous
?
anonymous
  • anonymous
distance from G till library write with U now you have.. \[\LARGE \tan30^{\circ}=\frac{300\sqrt3}{u}\] find U then use pythagoran theorem and you're done !
anonymous
  • anonymous
@JustCurious Do you understand it ?
anonymous
  • anonymous
not really
anonymous
  • anonymous
what you don't understand ?
anonymous
  • anonymous
Nevermind, thanks for your help!
anonymous
  • anonymous
... No hold on ! ... don't leave without knowing it ! I'll help you more !
anonymous
  • anonymous
\[\Large \tan30^{\circ}=\[\frac{\sqrt3}{3}\]\] so we have... \[\LARGE \frac{\sqrt3}{3}=\frac{300\sqrt3}{u}\] use cross multiply and you'll get \sqrt(3)*u=3*300*sqrt(3) can you solve it ..?

Looking for something else?

Not the answer you are looking for? Search for more explanations.