anonymous
  • anonymous
f(x) = e^(2x+1).sin(2x+1)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
what about it?
anonymous
  • anonymous
how do you simplify it?
anonymous
  • anonymous
I'm meant to be using calculus' product rule. I get so far then I get stuck when it comes to factoring.

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anonymous
  • anonymous
I don't think you can simplify this further, you can write the sine as the sum of two complex powers of e, but that doesn't get you any further.
anonymous
  • anonymous
You're saying the product rule, so you need to differentiate?
anonymous
  • anonymous
yes
anonymous
  • anonymous
I can differentiate it but struggle when it comes to factoring.
anonymous
  • anonymous
I get up to, sin(2x+1).2e^(2x+1) + e^(2x+1)2cos(2x+1) and then I'm stuck.
anonymous
  • anonymous
that's good so far, both terms have the factor 2e^(2x+1), you can take that out.
anonymous
  • anonymous
So 2e^(2x+1)(sin(2x+1)+cos(2x+1))
anonymous
  • anonymous
Thanks @Thomas9

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