anonymous
  • anonymous
Two parallel plates seperated by a distance of 5mm are kept at a potential difference of 50V.A particle of mass 10^(-15)kg and charge 10^(-11)C enters it with a velocity of 10^7 m/s.Find acceleration of particle
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1333567897583:dw| @experimentX why did he give velocity?
anonymous
  • anonymous
I mean there is only downward acceleration no matter how spped it comes in right?
JamesJ
  • JamesJ
The particles initial velocity here is irrelevant, yes.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
But doing like this I am not gettin the correct answer
anonymous
  • anonymous
Answer is 10^(8)m/s^2
JamesJ
  • JamesJ
btw, why are you showing gravity. The orientation of the plates in a gravitational field is not specified.
JamesJ
  • JamesJ
So let's talk about the electric field. What is it in this problem?
anonymous
  • anonymous
True but apparently all the questions here is preimplied that it is on earth because he gave mass
JamesJ
  • JamesJ
No, what the electric force will give you is the force. Then you use the mass to find the acceleration as F = ma
anonymous
  • anonymous
E is 10^4 N/C
anonymous
  • anonymous
Damn!I wish the'd specify as to whether it is on earth or not.
JamesJ
  • JamesJ
How did you calculate E?
experimentX
  • experimentX
but you are getting insane values
anonymous
  • anonymous
E*d=Potential difference
anonymous
  • anonymous
In this case
JamesJ
  • JamesJ
Right. I also agree with expX. The value of a is slightly crazy. This problem was not well written.
anonymous
  • anonymous
I am unsure as if to what he meant by entered with a velocity.I mean why did he give velocity.
experimentX
  • experimentX
velocity would be irrelevant ... though it would seem to produce same path as projectile motion and also gravitional force is also irrelevant ... for this high amount of vlaue
JamesJ
  • JamesJ
probably because there's a part (b) to the question about path.
experimentX
  • experimentX
unfortunately, i got the same value ...
anonymous
  • anonymous
Yeah that's why Iam thinking did he mean something else when he said that
JamesJ
  • JamesJ
For the record, the value of \[ a = 10^8 \ m/s \] is crazy because very quickly you will reach relativistic speeds where all kinds of adjustments to calculations need to be made. But even so, this is not outside the realm of possibility.
experimentX
  • experimentX
but this is crazy ... crazy amount of charge for 10^(-15) kg
anonymous
  • anonymous
10^-(11) Coulumb
experimentX
  • experimentX
10^(-11) = 10^8 electrons
experimentX
  • experimentX
still what is your answer?
experimentX
  • experimentX
maybe ... relativistic answer .. since the velocity is also relativistic ...???
anonymous
  • anonymous
Yeah the answer is acceleration is 10^8 m/s^2
experimentX
  • experimentX
then this is your answer .. i got the same value.
anonymous
  • anonymous
Oh I see ok.Then giving velocity was indeed useless.
experimentX
  • experimentX
pretty much .. though it looks interesting.
anonymous
  • anonymous
Yeah I mean what cause could it probably have even if part of the question was missing
experimentX
  • experimentX
the relativistic speed of the initial velocity ... measurement of length and time do not be the same.
anonymous
  • anonymous
Relative to?
experimentX
  • experimentX
Einstein's relativity ... when any object moves at speed comparable to speed of light, time seems a lit longer ... and lengths seems to contract.
anonymous
  • anonymous
Oh yeah
anonymous
  • anonymous
Got it
experimentX
  • experimentX
in other words, measurement do not be exact ... i would not like to speak too much on this part. because i lack so much knowledge
anonymous
  • anonymous
Yeah

Looking for something else?

Not the answer you are looking for? Search for more explanations.