anonymous
  • anonymous
The closest distance of approach of an alpha particle travelling with a velocity V toward a stationary nucleus is d.For the closest distance to be d/3 towards a stationary nucleus of double the charge the velocity of projection of the alpha particle has to be?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Can you explain what the question meant.I did not get it at all
experimentX
  • experimentX
|dw:1333570275508:dw|
anonymous
  • anonymous
After that repulsion?

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experimentX
  • experimentX
since both particles are positively charges, alpha particle will deaccelerate ... but it will reach a certain point. that is distance d
experimentX
  • experimentX
now if velocity of the alpha particle is increased then this distance will decrease ..
experimentX
  • experimentX
and also charge is increased by twice.
anonymous
  • anonymous
So what I need to find here is the potential at distance d away from nucleus causing all kinetic energy to change into potential energy which I can get from the potential
experimentX
  • experimentX
yep .. exactly.
experimentX
  • experimentX
most likely the problem is going towards ratio.
anonymous
  • anonymous
And should I take nucleus has charge Q
experimentX
  • experimentX
yes ,,,, i doesn't matter what you take.
anonymous
  • anonymous
Oh.Yeah I understand now

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