anonymous
  • anonymous
Surface charge density of a sphere of radius 10 cm is 8.85*10^-8 C/m^2.Find Potential at the centre of the sphere
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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experimentX
  • experimentX
hollow sphere or solid sphere??
anonymous
  • anonymous
Solid
experimentX
  • experimentX
potential is constant ... i suppose.

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More answers

anonymous
  • anonymous
Potential is constant at only the center because E=0 only at the centre
JamesJ
  • JamesJ
oh wait ... I'm wrong. E = 0 and hence the potential in the interior must be what it is at the surface.
anonymous
  • anonymous
But why?E is only 0 at the centre.Jusr near the centre Enot equal to 0
JamesJ
  • JamesJ
Yes, it must be because by Gauss's law, the electric flux for any closed surface inside the sphere is zero, because such a surface contains no charge.
experimentX
  • experimentX
first of all ... let's calculate the charge ... total charge
experimentX
  • experimentX
are we supposed to assume that charge is only at surface??
anonymous
  • anonymous
Yes
JamesJ
  • JamesJ
that is a fundamental result of electricity, that all charge is at the surface.
experimentX
  • experimentX
let me open my old book
anonymous
  • anonymous
All charge is at the surface if and only if it is a conductor.What if it is not
JamesJ
  • JamesJ
you're told the sphere has 1 value of electric field density, so even if it actually isn't a conductor, it looks like one right now.
JamesJ
  • JamesJ
**electric CHARGE density.
JamesJ
  • JamesJ
If you want to brush up on this, watch this juicy lecture: http://ocw.mit.edu/courses/physics/8-02-electricity-and-magnetism-spring-2002/video-lectures/lecture-4-electrostatic-potential-and-electric-energy/
anonymous
  • anonymous
Well I suppose that may be true
experimentX
  • experimentX
that would be a great problem in finding the total charge ... but if it were conductor .. our problem will be simplified.
JamesJ
  • JamesJ
it's easy: \( Q = \sigma A \)
anonymous
  • anonymous
Yeah here if it was volume charge density then it would be tough
JamesJ
  • JamesJ
and you need this. The electric potential at the surface is \[ V = \frac{kQ}{r} \] and that is the potential in the interior as well.
anonymous
  • anonymous
Yeah that's right.I was confused because I was thinking what if it was like charge is spread across the volume of the sphere
experimentX
  • experimentX
yeah i have the same answer
anonymous
  • anonymous
What is the answer?
JamesJ
  • JamesJ
\[ V = \frac{kA\sigma}{r} \] now calculate
anonymous
  • anonymous
Yeah Im not getting the correct answer
JamesJ
  • JamesJ
I guess you could simplify it even one more step to \[ V = 4 \pi k \sigma r \]

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