anonymous
  • anonymous
Find E at d=5 from the following graph
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1333574395820:dw|
experimentX
  • experimentX
V vs D ... potential vs distance??
anonymous
  • anonymous
Yep

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experimentX
  • experimentX
seems linear ... that's quite unusual ... since electrostatic forces are inverse square force.
experimentX
  • experimentX
let's try using ratio's
anonymous
  • anonymous
V is constant from 2 to 4 means E=0 at that region?
experimentX
  • experimentX
V6/V5 = r5/r6 ???
experimentX
  • experimentX
yes ... E is derived form V by differentiating with respect to r
anonymous
  • anonymous
So what is E at d=5?
experimentX
  • experimentX
are you sure it's a staight line??
anonymous
  • anonymous
Yeah
experimentX
  • experimentX
it shouldn't be zero at 6
anonymous
  • anonymous
Why?
experimentX
  • experimentX
thats quite unusual ... we usually have hyperbolic or ... what do we call this |dw:1333575004239:dw| type of graph.
anonymous
  • anonymous
Yeah but here this is the potential caused by many charges perhaps
experimentX
  • experimentX
let's see what it could be ... if it's linear that the answer is average between 4 and 6, but still it's worth it to see what causes such potential
anonymous
  • anonymous
huh how is it the average?
anonymous
  • anonymous
And yeah perhaps there is an electric field by a certain group of charges that produce this V
experimentX
  • experimentX
since the graph is linear ..
anonymous
  • anonymous
We need E
experimentX
  • experimentX
V/d = E
experimentX
  • experimentX
d = 1 ... mostlikely we have object in the costant V
anonymous
  • anonymous
That was my first step.But that gives the answer as E=1
anonymous
  • anonymous
Answer is 2.5 V/m
experimentX
  • experimentX
V = 2.5 d=1 ... so my hunch was right
anonymous
  • anonymous
What?how
experimentX
  • experimentX
both from graph
anonymous
  • anonymous
Oh no i misread it
experimentX
  • experimentX
V = average on 4 and 6, which will give 5/2
anonymous
  • anonymous
Here he gave another similar one.The electric potential decreases uniformly from 120 V to 80 V as one moves on the x axis from x=-1 cm to x=+1 c.Find E at origin.btw how much would you rate the difficulty of the questions I asked out of 5
anonymous
  • anonymous
That is V
anonymous
  • anonymous
huh?what?
experimentX
  • experimentX
was it rated V out of V??
anonymous
  • anonymous
I didnt get you
experimentX
  • experimentX
just forget it .. it was nothing
anonymous
  • anonymous
What is the answe rto this one
experimentX
  • experimentX
100V
anonymous
  • anonymous
Need to find E not V
experimentX
  • experimentX
20
anonymous
  • anonymous
how?
experimentX
  • experimentX
wait ... what is the answer??
anonymous
  • anonymous
20
experimentX
  • experimentX
E = dV/dr
experimentX
  • experimentX
(120-80)/(1--1)
experimentX
  • experimentX
E = -dV/dr
anonymous
  • anonymous
Yeah

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