If sin (B) = -1/3 with B in QIII, find csc (B/2).

If sin (B) = -1/3 with B in QIII, find csc (B/2).

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\[\sin \left( \frac{B}{2} \right)=\sqrt{\frac{1-\cos B}{2}}\]

Right, but how does this help find csc?

\[\csc \left( \frac{B}{2} \right)=\frac{1}{\sin \left( \frac{B}{2} \right)}\]

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