Geometry_Hater
  • Geometry_Hater
Use properties of logarithms to expand the following expressions. log1 6y I dont know what to do...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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lgbasallote
  • lgbasallote
hmm..first ask yourself..do you see any operation her? (+, -, x, /)
anonymous
  • anonymous
I think this is the same as saying 6y to what power equals 1
Geometry_Hater
  • Geometry_Hater
i see multiplication

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lgbasallote
  • lgbasallote
good! @Geometry_Hater and that means....? @IAmCorbin it's 1 raise to something equals 6y
Geometry_Hater
  • Geometry_Hater
i dont know .....you multiply 6y by something?
anonymous
  • anonymous
what power do you raise 1 to to get 6y?
lgbasallote
  • lgbasallote
log_a (bc) = log_a b + log_a c any ideas now?
Geometry_Hater
  • Geometry_Hater
6?
anonymous
  • anonymous
log1(6) + log1(y) = log1 (6y)
Geometry_Hater
  • Geometry_Hater
is that the answer?
anonymous
  • anonymous
that still needs to be solved
Geometry_Hater
  • Geometry_Hater
what do i do to that then
anonymous
  • anonymous
I'm not sure what to raise 1 to to get 6
Geometry_Hater
  • Geometry_Hater
my paper just says log 6y
anonymous
  • anonymous
which is the same as log(6) + log(y) according to @lgbasallote
Geometry_Hater
  • Geometry_Hater
yeah this is where my mind goes blank
anonymous
  • anonymous
I don't know if this problem can be simplified anymore. One raised to anything is always 1
lgbasallote
  • lgbasallote
that's the simplest it gets

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