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needhelpinmath

  • 4 years ago

Solve for x in terms of a, b, and c. ax^2+bx+c=0

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  1. Akshay_Budhkar
    • 4 years ago
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    Using the quadratic equation the solution for this problem will be \[x={-b \pm \sqrt{b^2 - 4ac}} \over 2a\]

  2. Akshay_Budhkar
    • 4 years ago
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    \[x= {{-b \pm \sqrt {b^2 - 4ac}} \over 2a }\] is what i mean

  3. needhelpinmath
    • 4 years ago
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    o ok then thanks

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