Here's the question you clicked on:
needhelpinmath
Solve for x in terms of a, b, and c. ax^2+bx+c=0
Using the quadratic equation the solution for this problem will be \[x={-b \pm \sqrt{b^2 - 4ac}} \over 2a\]
\[x= {{-b \pm \sqrt {b^2 - 4ac}} \over 2a }\] is what i mean
o ok then thanks