anonymous
  • anonymous
I need some help with this.. Its complicated to write but here is a picture of it. I have the answer but I need the step by step solution please. Simplify: http://miniurl.org/oY7 Answer: http://miniurl.org/tzG
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
NotTim
  • NotTim
wowsers
NotTim
  • NotTim
i think though, that you can subtract the exponents somehow
anonymous
  • anonymous
Factor both expressions in the numerator fraction by difference of squares, invert the denominator fraction and set up for multiplication. There will be enough factors that cancel to leave you with the answer you have.

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anonymous
  • anonymous
What do you mean by difference of squares exactly? I'm more of a visual, do you have a picture by chance or can you give an example?
anonymous
  • anonymous
Difference of squares: a^2-b^2=(a+b)(a-b). In this case, a=x+y or x-y, depending on whether you are considering the numerator or denominator of the expression in the numerator of the overall problem.
anonymous
  • anonymous
\[\frac{\frac{(x-y)^2-z^2}{(x+y)^2-z^2}}{\frac{x-y+z}{x+y-z}}=\frac{(x-y-z)(x-y+z)}{(x+y-z)(x+y+z)}\frac{(x+y-z)}{(x-y+z)}\]
anonymous
  • anonymous
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