LaddiusMaximus
  • LaddiusMaximus
Apply L'Hôpital's Rule to evaluate the following limit. It may be necessary to apply it more than once. lim x->inf (x-6)/(5-8x)
Mathematics
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katieb
  • katieb
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LaddiusMaximus
  • LaddiusMaximus
why would that be on the bottom?
LaddiusMaximus
  • LaddiusMaximus
walk me through it please
anonymous
  • anonymous
L'Hôpital's Rule is when you take the derivative of the top and bottom and then evaluate the limit if it is at x=>0, inf, or -inf. The derivative of this is found using the quotient rule. Not sure if you don't know L'Hôpital's Rule or the quotient rule. If you don't know the quotient rule I'll be happy to explain =)

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LaddiusMaximus
  • LaddiusMaximus
I know the quotient rule. I wasnt sure how you got -1/8
anonymous
  • anonymous
The little mark means the derivative
amistre64
  • amistre64
whats the derivative of the top?
LaddiusMaximus
  • LaddiusMaximus
1
amistre64
  • amistre64
whats the deriveative of the bottom?
LaddiusMaximus
  • LaddiusMaximus
8
amistre64
  • amistre64
forgot a sign with that, look again
LaddiusMaximus
  • LaddiusMaximus
-1/8
amistre64
  • amistre64
\[L'Hop=lim\frac{t'}{b'};\ \lim_{x\to inf}\frac1{-8}=-\frac{1}{8}\]
anonymous
  • anonymous
Ahh! Completely forgot it was different. He's right, take the derivative of the top and bottom *separately*, sorry about that.
LaddiusMaximus
  • LaddiusMaximus
no worries. have a new one if you are interested

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