anonymous
  • anonymous
Find the indefinite integral of: [sinxcosx] / [(sinx)^4 + (cosx)^4)] I would like a hint please, not the answer.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1333589544364:dw|
anonymous
  • anonymous
Not the answer please. Just a hint.
anonymous
  • anonymous
Perhaps an identity or two.

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anonymous
  • anonymous
i dont know if this helps or not, but:\[\sin^4(x)+\cos^4(x)=1-2\sin^2(x)\cos^2(x)\]
anonymous
  • anonymous
sin^2(x) is equal to (1-cos2x)/2 and cos^2(x)= (1+cos2x)/2
anonymous
  • anonymous
Ok so are you suggesting that I switch everything to double angles, and then simplify?
anonymous
  • anonymous
That's prob. how I would go about it. sin^2(x)= ((1-cos2x)/2)^2. It's long, but I can't think of a shorter way to integrate sin^4
anonymous
  • anonymous
Ok I also had this question as well: Find the indefinite integral of: [secx + cos(2x)]/[sinx + secx]. Again, I would like a hint.
anonymous
  • anonymous
Try this one if the other one is too much.
anonymous
  • anonymous
|dw:1333590124827:dw|
anonymous
  • anonymous
Wolfram alpha is outputting hyperbolic functions for this. We did not cover those types of functions so I think I will disregard these.
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=Find+the+indefinite+integral+of+%28secx+%2B+cos2x%29%2F%28sinx+%2B+secx%29

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