anonymous
  • anonymous
∫ (5 / x² -4/x) dx I'm confused as to what to do. Do I begin by taking the anti derivative and if so how it is done?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
5x^-2 - 4x^-1 took the anti derivative and got 5x^-1/-1 - 4x^0/0. Do I ignore the second term since it is undefined?
kropot72
  • kropot72
The second term in your putative answer is \[\infty\]. Then you should add the constant of integration as the third term of the answer.
anonymous
  • anonymous
Im confused as to how an integer divided by zero is equivilant to infinity?

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kropot72
  • kropot72
0/0 is indeterminate (undefined). However any real number divided by zero will give the result of infinity - subject to a positive or negative sign.
kropot72
  • kropot72
Sorry. The second term in your putative answer should be: \[-(4\times \ln x)\]
anonymous
  • anonymous
ohh okay that makes much more sense
Callisto
  • Callisto
∫ (5 / x² -4/x) dx = ∫ (5x^-2 -4/x) dx =∫ (5x^-2 )dx -∫ (4/x) dx = 5 [x^(-2+1)] / (-2+1) -4ln|x| +C = -5 /x - 4ln|x| +C
kropot72
  • kropot72
You're welcome. The integral of 1/x does not follow the usual rule for integration.
anonymous
  • anonymous
Thanks guys I really appreciate youre help!

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