anonymous
  • anonymous
Please help! Sketch the graph of f(x)=x^2-x by locating the x and y intercepts and the extreme point of the parabola. The x-intercept(s): a. = 0 and 1 b. does not exist c. = 0 d. = 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Carniel
  • Carniel
We cant graph for you. It would be basically giving you the answer. You wouldn't learn anything from that.
anonymous
  • anonymous
Can you explain to me how I would do this though?
anonymous
  • anonymous
Oh wait, I think I got it... Can you verify? 0 and 1?

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Carniel
  • Carniel
All you have to do is graph it. Idk how to explain how you graph.... Im a on hands person
anonymous
  • anonymous
here's a hint on graphing parabolas... they all have basically the same shape and they all either have a maximum or minimum... minimum if the coeficient of the x^2 term is positive in which case the graph opens upward. if the coeficient is negative, then parabola opens downward and it has a maximum.
anonymous
  • anonymous
Oh o.k. Thank you for the useful advice!

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