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NotTim Group TitleBest ResponseYou've already chosen the best response.0
i was thinking: why not just use dummy variables, like k=10, i=9 and m=3, but is there something deeper?
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Nope, that is the correct course of action. That would be the only way to prove by example.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
i was thinking that it was MUCH more complex than that..
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
If (k + m)u = ku + mu , you should be able to set variables k,m and u equal to any random numbers and both sides should come out equal.
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
I doubt if it is any more complex than that.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
this was simple. to me, simple means secretly hard. thank you for clarifying
 2 years ago
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