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NotTim
 2 years ago
Best ResponseYou've already chosen the best response.0i was thinking: why not just use dummy variables, like k=10, i=9 and m=3, but is there something deeper?

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1Nope, that is the correct course of action. That would be the only way to prove by example.

NotTim
 2 years ago
Best ResponseYou've already chosen the best response.0i was thinking that it was MUCH more complex than that..

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1If (k + m)u = ku + mu , you should be able to set variables k,m and u equal to any random numbers and both sides should come out equal.

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1I doubt if it is any more complex than that.

NotTim
 2 years ago
Best ResponseYou've already chosen the best response.0this was simple. to me, simple means secretly hard. thank you for clarifying
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