anonymous
  • anonymous
Simplify the following expression. \[\sqrt{-18}\sqrt{-72}\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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lgbasallote
  • lgbasallote
\[\sqrt{(-18)(-72)}\] can you use a calculator?
anonymous
  • anonymous
maybe
anonymous
  • anonymous
I DONT HAVE ONE

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anonymous
  • anonymous
HELP PLEASE
chris
  • chris
I think the question was more - are you allowed to on this problem.
lgbasallote
  • lgbasallote
okay..i'll do this the manual way...
lgbasallote
  • lgbasallote
yuppp that's what i meant thanks @chris :D
chris
  • chris
np =). and I think we're assuming not allowed heh.
Zarkon
  • Zarkon
\[\sqrt{-18}\sqrt{-72}\neq \sqrt{(-18)(-72)}\]
lgbasallote
  • lgbasallote
oh man..made a mistake in one :O
anonymous
  • anonymous
WHAT WAS THE MISTAKE
lgbasallote
  • lgbasallote
isn;t it @Zarkon ? isn't \[\sqrt{a}\sqrt{b} = \sqrt{(a)(b)}\]?
Zarkon
  • Zarkon
if \(a,b\ge 0\)
lgbasallote
  • lgbasallote
oh..hmm..yeah..this is imaginary now that i think about it..
Zarkon
  • Zarkon
\[\sqrt{-18}\sqrt{-72}\] \[=i\sqrt{18}\times i\sqrt{72}\] \[=i^2\sqrt{18}\times \sqrt{72}\] \[=-\sqrt{18\times 72}\] \[=-\sqrt{18\times 2\times 36}\] \[=-\sqrt{36\times 36}=-36\]
lgbasallote
  • lgbasallote
hmm yeah..went pretty careless there..sorry :)
anonymous
  • anonymous
im confused
anonymous
  • anonymous
THANKS EVERYONE
lgbasallote
  • lgbasallote
\[\sqrt{-a} = i \sqrt{a}\] he just factored an i..then when i^2..it became -1...my other mistake was the 2 i pulled out..i wrote 4 so my answered doubled..do you get it now?
anonymous
  • anonymous
YES
anonymous
  • anonymous
|dw:1333603586979:dw|

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