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I THINKING OF treating it as a parallel thing, but that's not correct, is it?

\[{\vec u\over||\vec u||}\]makes it a unit vector, did you know that?

what's that.

dividing by the norm/magnitude of the vector

Unit vector parallel to \(\vec{u}\) is : \( \frac{1}{\sqrt{13}} <2,3> \)

ok...
I don't understand, but I don't think I really need further explaination @TuringTest

Also, what did you type FFM? That looks...strange

But there is one one unique vector (parallel) isn't ?

what is the magnitude of u ?

[2,3]

to amke a vector into a unit vector, divide by its magnitude

*make

aww...what exactly is a uni vector. I though the point [2,3] was a vector itself...

A unit vector is a vector that has a length (i.e. "magnitude) of 1

ok. um. gimme a moment to do the math here

wait, how do i divide [2,3] by sqrt 13?

do each component individually: it is a scalar multiplication

im really fuzzy on this. I divide 2 by sqrt 13, and then 3 by sqrt 13 right?

yep, and those will be you new components

umm.srry. pencil is breaking on me here...

try a calculator ;)

im going to get a new pencil. bak in a flash

\[{2\over\sqrt{13}}\]just requires a calculator!!!!

argh. srry. wat nxt now

got [0.55,0.83]

hooray

I guess you don't wanna explain both methods?

wat do yu mean "exact same trick"

oohhh...i see. scalar multitplier of -2.

ok.

so, v is parallel to u. actually. wait. we already got the answer. thats magical.

yeah you got it :)

wait...what's the "first" way.

does that mean its parallel to u?

though sorry, now that I reread the question v isn't even important

scalar multiples only change the length of the vector

hence they do not change whether or not they are parallel

unit vectors parallel to*

no, unless there is some huge exception that is slipping my mind...

scalar multiplication of a vector changes only \(direction\) and/or \(magnitude\) (i.e. length)

so i pick, say [3,2,6]. Then it is parallel to [6,4,12]?

look at it like slope

ok then, glad I could help
rest well, a weary mind is not terribly useful in mathematics ;)

should i sleep now, and risk not studying later, or study, but not sleep ever?