anonymous
  • anonymous
\[A=(2yz)i-(x ^{2}y)j+(xz ^{2})k,B=(x ^{2})i+(yz)j-(xy)k\]what is\[(B.\nabla)A\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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TuringTest
  • TuringTest
\[(\vec B\cdot\nabla)\vec A\]?
TuringTest
  • TuringTest
...as in the scalar multiple of \(\text{div}\vec B\) with \(\vec A\) ???
anonymous
  • anonymous
should be, lol

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anonymous
  • anonymous
i cant obtain the answer provided by my tutor
TuringTest
  • TuringTest
do you know how to get the divergence of \(\vec B\)\[\text{div}\vec B=?\]
anonymous
  • anonymous
yea. i get \[(2x+z+0)\]
anonymous
  • anonymous
or i get it wrongly LOL
TuringTest
  • TuringTest
nope that's right
anonymous
  • anonymous
then the scalar multiplication, i get\[(2yz(2x+z), -x ^{2}y(2x+z), 0)\]but the answer provided is \[(2y(z ^{2}-xy), -x ^{2y}(2x+z), x ^{2}z(z-2y))\]
TuringTest
  • TuringTest
well that's not \[(\nabla\cdot\vec B)\vec A\]
TuringTest
  • TuringTest
let's see if it'swell that's not \[(\nabla\cdot\vec A)\vec B\]real quick maybe?
anonymous
  • anonymous
u mean the answer's has problem?
TuringTest
  • TuringTest
yeah, if the question is\[(\text{div}\vec B)\vec A\]then the book made a mistake or something ...unless I've lost my mind, which happens from time to time at 3:30am
anonymous
  • anonymous
if u dont mind, 1more question?
TuringTest
  • TuringTest
sure, try me
anonymous
  • anonymous
given\[\phi =2x ^{2}yz ^{3}\] then what is \[(A \times \nabla)\phi\]
anonymous
  • anonymous
the cross product i get\[(z ^{2}-2y)j+(2z+2xy)k\], correct?
TuringTest
  • TuringTest
is that just\[\vec A\times\nabla\]up there? 'cause that's right as far as I can see for that, but I don't see \(\phi\)
anonymous
  • anonymous
yes its vector of A crossed with nabla, and outside the phi is given as\[2x ^{2}yz ^{3}\]
anonymous
  • anonymous
T_T the test is 2mr and his tutorial aint helping anytg lol
TuringTest
  • TuringTest
lol just multiply be \(\phi\) as a scalar now and I guess that's it kinda dumb problem if you ask me
TuringTest
  • TuringTest
it want's the negative curl and a simple scalar multiplication just an exercise I guess
anonymous
  • anonymous
i get \[2x ^{2}yz ^{3}(z ^{2}-2y)j+2x ^{2}yz ^{3}(2z+2xy)k\] the answer given is \[-2x ^{3}z ^{2}(3xy ^{2}+z ^{3})i+4x ^{2}yz ^{2}(z ^{2}-3y)j+4x ^{2}yz ^{3}(z+xy)k\]._.
anonymous
  • anonymous
the i popped out from nowhere
TuringTest
  • TuringTest
we are not understanding what they want it seems
TuringTest
  • TuringTest
now the problem is to figure out what they are asking lol because it ain't\[(\vec A\times\nabla)\phi\]with phi as a scalar multiple
TuringTest
  • TuringTest
like you said, the \(\hat i\) component is clearly zero after \(\nabla\times A\)
anonymous
  • anonymous
i think i'll just leave those aside.. lol. mayb my tutor is blur afterall
TuringTest
  • TuringTest
I feel bad I can't help, but something is amiss here better luck next time, promise as for me, it's goodnight :)
anonymous
  • anonymous
kk nitez

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