Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

A 10 A current is charging a 1.0-cm-diameter parallel-plate capacitor. What is the magnetic field strength at a point 2.0 mm from the center of the capacitor?

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

I thought it was "electro-static" field within the capacitor this a trick question?
i haven't even learned that term yet so not a trick question.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

i used Bpir^2=u_0*I... oh i think i use distance for r? i used radius of plates nd got the wrong answer
same as electric field........ I can see electromagnetic field circling the conductor attached to each electrode of the capacitor, what kind pattern would exist for an electromagnetic field within the dielectric (air in this case) of the capacitor? Is this a physics or an electrical engineering question?
it's physics, accidentally posted it here
since it's not stated otherwise, it seems like uniform fields
Interesting, I have retired from the electronics field, and thankfully have not run into that question. Good luck, there are some physics savvy people here, JamesJ being one of them.

Not the answer you are looking for?

Search for more explanations.

Ask your own question