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heeeeeeeeelllllllllllpppppppppp! mr. abato is constructing the walkway on the three sides of his garden. how wide should the two remaining sides be if he wants the total area of the walkway to be one-half the area of his garden???? answers a. 1 3/4ft b. 2ft c.2 1/4ft d. 2 1/2ft

Mathematics
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|dw:1333686970608:dw|
\[A_G=2A_W\]
how wide should what be?

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thats supposed to b the equation right?
the big "A" and the sub letter wats that supposed 2b 4?
area of the walk way \[=A_W \] area of the garden \[=A_G\]
ooo
ok how do u knw in which order to place the #s? in the equation
i not sure i understand that question
like since u created separate equations....how do u knw which #s to put in them?
i am making this up as i go along
well.....really? thats nice 2 know (head shake)
ok so i have made a huge mistake, \[A_W = (12ft+3ft)×(20ft+2xft) -A_G\]
ok so will this 'made up' equation of urs help me w/ this problemm? jus asking
is that a 3 ft walkway at the top of page?
sure is
wait... so is the garden a pentagon?
nope.rectangle
cool. lets start from the start. Picture , good we are solving a system of 3 equations, two are the equation for the area, an one is the relationship between the two areas. From the diagram we can see that 1. the area of the garden is the area of the rectangle ={width} x {length} \[A_G=20ft \times 12ft\]\[=120ft^2\] 2. the area of the walkway is the area of the rectangle minus the area of the garden \[A_W = (2x+20)ft \times (12+3)ft -A_G\]\[ = 2(x+10)ft\times 15ft-120ft^2\] 3. the question states that the area of the walkway is half the area of the garden\[A_W=\frac{1}{2}A_G\] \[SSubsitute 1. and 2. into 3. and solve
i dont know why but i keep getting x is negative 4 ,
where is the (2x+20)ft coming from again?
|dw:1333689848029:dw|
ok but like in step 1. u wrote (2x+20)ft and i kinda confused isnt it supposd 2 b 3x?
i mean step 2 my bad
is that a 2x on the left?
no its an 'x' its an 'x' on both sides
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