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lilly21

  • 2 years ago

heeeeeeeeelllllllllllpppppppppp! mr. abato is constructing the walkway on the three sides of his garden. how wide should the two remaining sides be if he wants the total area of the walkway to be one-half the area of his garden???? answers a. 1 3/4ft b. 2ft c.2 1/4ft d. 2 1/2ft

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  1. lilly21
    • 2 years ago
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    |dw:1333686970608:dw|

  2. UnkleRhaukus
    • 2 years ago
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    \[A_G=2A_W\]

  3. mridrik
    • 2 years ago
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    how wide should what be?

  4. lilly21
    • 2 years ago
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    thats supposed to b the equation right?

  5. lilly21
    • 2 years ago
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    the big "A" and the sub letter wats that supposed 2b 4?

  6. UnkleRhaukus
    • 2 years ago
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    area of the walk way \[=A_W \] area of the garden \[=A_G\]

  7. lilly21
    • 2 years ago
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    ooo

  8. lilly21
    • 2 years ago
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    ok how do u knw in which order to place the #s? in the equation

  9. UnkleRhaukus
    • 2 years ago
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    i not sure i understand that question

  10. lilly21
    • 2 years ago
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    like since u created separate equations....how do u knw which #s to put in them?

  11. UnkleRhaukus
    • 2 years ago
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    i am making this up as i go along

  12. lilly21
    • 2 years ago
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    well.....really? thats nice 2 know (head shake)

  13. UnkleRhaukus
    • 2 years ago
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    ok so i have made a huge mistake, \[A_W = (12ft+3ft)×(20ft+2xft) -A_G\]

  14. lilly21
    • 2 years ago
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    ok so will this 'made up' equation of urs help me w/ this problemm? jus asking

  15. UnkleRhaukus
    • 2 years ago
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    is that a 3 ft walkway at the top of page?

  16. lilly21
    • 2 years ago
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    sure is

  17. pythagoras123
    • 2 years ago
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    wait... so is the garden a pentagon?

  18. lilly21
    • 2 years ago
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    nope.rectangle

  19. UnkleRhaukus
    • 2 years ago
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    cool. lets start from the start. Picture , good we are solving a system of 3 equations, two are the equation for the area, an one is the relationship between the two areas. From the diagram we can see that 1. the area of the garden is the area of the rectangle ={width} x {length} \[A_G=20ft \times 12ft\]\[=120ft^2\] 2. the area of the walkway is the area of the rectangle minus the area of the garden \[A_W = (2x+20)ft \times (12+3)ft -A_G\]\[ = 2(x+10)ft\times 15ft-120ft^2\] 3. the question states that the area of the walkway is half the area of the garden\[A_W=\frac{1}{2}A_G\] \[SSubsitute 1. and 2. into 3. and solve

  20. UnkleRhaukus
    • 2 years ago
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    i dont know why but i keep getting x is negative 4 ,

  21. lilly21
    • 2 years ago
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    where is the (2x+20)ft coming from again?

  22. UnkleRhaukus
    • 2 years ago
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