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louis413

  • 4 years ago

Let log2=0.428 and log3=0.519, what is the approximate value of log24?

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  1. CoCoTsoi
    • 4 years ago
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    log 24 =log(2)(2)(2)(3) = 3log2 + log 3 = 3(0.428)+0.519

  2. campbell_st
    • 4 years ago
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    24 = 2^3 x 3 \[\log(2^3 \times3) = \log 2^3 + \log 3 = 3 \times \log(2) + \log 3\]

  3. louis413
    • 4 years ago
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    thank yalll

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