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Renee99
Group Title
How can you tell when a quadratic equation has no real solutions?
A. when the radicand is negative
B. when b in the quadratic formula is greater than the radicand
C. when the radicand equals zero
D. when the radicand is not a perfect square
I believe the answer is A? is that right?
 2 years ago
 2 years ago
Renee99 Group Title
How can you tell when a quadratic equation has no real solutions? A. when the radicand is negative B. when b in the quadratic formula is greater than the radicand C. when the radicand equals zero D. when the radicand is not a perfect square I believe the answer is A? is that right?
 2 years ago
 2 years ago

This Question is Closed

campbell_st Group TitleBest ResponseYou've already chosen the best response.3
its A using the discriminant \[b^2  4ac\] < 0 no real solutions the radical will be negative
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
whats radicand anyway??
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
i go with campbell
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.3
the square root symbol
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
\[x=\frac{b \pm \sqrt{b^24ac}}{2a}\]
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
Thanks!! :) I also have this one... For which value of x does the graph of y = 2x2 − 7x + 6 cross the xaxis? A. −3/2 B. −2/3 C. 2 D. 3 I think its C.
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
\[b^24ac\] is the discriminant
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
You are correct.
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.3
you can substitute each value to find y = 0 or factorise (2x  3)(x  2) = 0 x = 3/2 and 2
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
Thanks so much, here's another one i'm stuck on... What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth? A. x ≈ −3.23 and x ≈ 0.23 B. x ≈ −2.72 and x ≈ −0.28 C. x ≈ 0.28 and x ≈ 2.72 D. x ≈ −0.23 and x ≈ 3.23 I think its C, but I'm not sure??
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.3
put it in standard form 4x^2 + 12x + 3 = 0 use the general quadratic formula \[x = (b \pm \sqrt{b^2  4ac})/2a\] in your question a = 4, b = 12 and c = 3
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
C is correct.
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
thanks so much!! :)
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Both roots are negative.
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
B? Really? are you sure?
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
Okay, i'll trust you! :)
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
\[x=\frac{12\pm \sqrt{96}}{8}\]
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
I have one more question that's really confusing me, would you mind sticking around for one more?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
\[x=\frac{12+9.80}{8} or x=\frac{129.80}{8}\]
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
*note* don't ask me why the numbers are spreed out like that, I just copied and pasted it onto here, that how it looks on my paper. Which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring? −b b2 − 4ac 2a Use the part of the quadratic formula that you chose above and find its value given the following quadratic equation: 2x2 + 7x + 3 = 0
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
is that the answer?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Well which part would you choose? b? 2a????
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
\[b^24ac=7^24(2)(3)=4924=25\]
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
I don't know... This is really confusing me for some reason...
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
so the answer is b^24ac?
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
I'm still confused... :/
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
or is the answer this: b²  4ac = (7)²  4(2)(3) = 49  24 = 25.
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
The discriminant, which is b^24ac, is the part of the quadratic formula which tells you about the roots.
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Do you understand that the question has two parts? READ THE QUESTION!!!
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
PART 1: Which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
The answer to that is :b^24ac
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
PART 2: Use the part of the quadratic formula that you chose above and find its value given the following quadratic equation: 2x2 + 7x + 3 = 0
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
The answer to that is 25
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
ohhh okay, I understand now
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
Thank you!!
 2 years ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.0
I just wasn't looking at the problem correctly, sorry for the confusion and thanks again for breaking it down for me
 2 years ago
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