anonymous
  • anonymous
Puzzle #101
Meta-math
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
Question 2. What if Randall goes first? Question 3. What if it's an m×n grid? \[\color{gray}\Huge{\text{___________________________________________________________________________}}\] Source: http://spikedmath.com/puzzle-006.html
1 Attachment
anonymous
  • anonymous
can mike darken only the squares he has written numbers into or all the squares with the largest number in any row?
anonymous
  • anonymous
The ones with largest number I think.

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anonymous
  • anonymous
For question 1 and 2, the second player has the winning strategy. For any turn, if Player 1 puts a number in row i, Player 2 needs to put a number in the same row. In each row, make the first three spots group 1, and the second 3 spots group 2. Whichever group Player 1 puts the number in, Player 2 puts his number in the other group. Now, in the odd rows, Player 2 can force the black square to end up in Group 1 since: 1) If player 1 puts numbers in group 1, player 2 responds with smaller numbers in group 2 2) If player 1 puts numbers in group 2, player 2 responds with larger numbers in group 1. In the even rows, do the opposite (switch the words smaller and larger), and this will result in the black squares ending up in group 2. If player 2 plays like this, the only possible way player 1 can win is if the grid looks like this:|dw:1335510717037:dw|So to counter this, all player 2 has to do is change his strategy in the sixth row, and make sure the black square doesnt end up in column 2, 3, or 4. to accomplish this task, make group 1 columns 2, 3, and 4, and group 2 columns 1, 5, and 6. If player 2 plays like he did in the other even rows, this will result in his victory.
anonymous
  • anonymous
To be a little more specific about what size numbers player two should be placing, they should be the largest in the row if he's putting a larger number in, and the smallest in the row if hes putting a small number in.
anonymous
  • anonymous
|dw:1335512114034:dw|for anyone who wants to play lol, use the strategy :P
ParthKohli
  • ParthKohli
@Ishaan94 How did you make that
?
anonymous
  • anonymous
lol, it's a stupid way using \(\LaTeX\).
ParthKohli
  • ParthKohli
Oh, that's LaTeX. :P

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