## Hannah_Ahn 2 years ago If y-3, y, and 3y+4 are consecutive terms in a geometric sequence, determine the value(s) of y.

1. Mertsj

$\frac{y}{y-3}=\frac{3y+4}{y}$ $y^2=3y^2-5y-12$ $2y^2-5y-12=0$ $(2y+3)(y-4)=0$ $y=\frac{-3}{2} or y = 4$