A community for students.
Here's the question you clicked on:
 0 viewing
cwrw238
 2 years ago
Differentiate sinsinsin2x
cwrw238
 2 years ago
Differentiate sinsinsin2x

This Question is Closed

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0i'm confused with this one i guess you use the chain rule?

Noliec
 2 years ago
Best ResponseYou've already chosen the best response.1You do, it's horrifying! :(

Noliec
 2 years ago
Best ResponseYou've already chosen the best response.1d(sin(sin(sin(2x))))/dx=dsinu/du*du/dx u=sin(sin(2x)) and dsinu/du=cosu

Noliec
 2 years ago
Best ResponseYou've already chosen the best response.1And then you apply it once more but that gets too messy for me to type  bound to make a mistake. Hehe, hope my answer helped to some extent atleast; good luck!

Noliec
 2 years ago
Best ResponseYou've already chosen the best response.1Using the chain rule three times.

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0ugh  yes! ill try that

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.1you should be getting \[2 \cos (2 x) \cos (\sin (2 x)) \cos (\sin (\sin (2 x)))\]

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0i got 2cos(sinsin2x)*cos(sin2x)*2cos2x

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0not quite i've got one extra '2'

Noliec
 2 years ago
Best ResponseYou've already chosen the best response.1Oh right, missed that one, sorry

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0i think sam is right though

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0yea the first 2 is wrong

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0i did it in steps from left to right

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.0Sam's correct! You should take derivative from RIGHT to left: ( sin2x )' = 2 cosx sin ( sin2x) ' = 2 cosx * cos ( sin2x ) sin [ sin ( sin2x)] ' = 2 cosx * cos ( sin2x ) * cos [ sin ( sin2x)] Just go step by step, you won't miss it :)

Aron_West
 2 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=Differentiate+sin%28sin%28sin%282x%29%29%29
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.