yrivers36
Solve each equation symbolically. With explanation please.
sqrt (x)+1=sqrt (x+2)



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Kreshnik
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hint...
\[\LARGE \sqrt x+1=\sqrt{x+2}\] square both sides..

yrivers36
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Im not sure but I think I should foil left side of problem

yrivers36
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\[(\sqrt{x}+1)(\sqrt{x}+1)x+2\]

yrivers36
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thats an = in front of x

Kreshnik
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\[\LARGE (\sqrt x+1)^2=(\sqrt{x+2})^2\]
\[\LARGE (\sqrt x)^2+2\cdot \sqrt{x}\cdot 1+1^2=x+2\]
\[\LARGE x+2\cdot \sqrt{x}=x+21\]
\[\LARGE 2\cdot \sqrt{x}=xx +21\]
\[\LARGE 2\cdot \sqrt{x}=1\]
\[\LARGE \sqrt{x}=\frac12\]
square both sides and there you go :)

Kreshnik
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can you do it ?

yrivers36
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solution manuel says x = 1/4

Kreshnik
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that's correct. Well done ! ;)

yrivers36
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Thank you once again :)

Kreshnik
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Glad to help :)