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yrivers36

  • 2 years ago

Solve each equation symbolically. With explanation please. sqrt (x)+1=sqrt (x+2)

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  1. Kreshnik
    • 2 years ago
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    hint... \[\LARGE \sqrt x+1=\sqrt{x+2}\] square both sides..

  2. yrivers36
    • 2 years ago
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    Im not sure but I think I should foil left side of problem

  3. yrivers36
    • 2 years ago
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    \[(\sqrt{x}+1)(\sqrt{x}+1)-x+2\]

  4. yrivers36
    • 2 years ago
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    thats an = in front of x

  5. Kreshnik
    • 2 years ago
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    \[\LARGE (\sqrt x+1)^2=(\sqrt{x+2})^2\] \[\LARGE (\sqrt x)^2+2\cdot \sqrt{x}\cdot 1+1^2=x+2\] \[\LARGE x+2\cdot \sqrt{x}=x+2-1\] \[\LARGE 2\cdot \sqrt{x}=x-x +2-1\] \[\LARGE 2\cdot \sqrt{x}=1\] \[\LARGE \sqrt{x}=\frac12\] square both sides and there you go :)

  6. Kreshnik
    • 2 years ago
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    can you do it ?

  7. yrivers36
    • 2 years ago
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    solution manuel says x = 1/4

  8. Kreshnik
    • 2 years ago
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    that's correct. Well done ! ;)

  9. yrivers36
    • 2 years ago
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    Thank you once again :)

  10. Kreshnik
    • 2 years ago
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    Glad to help :)

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