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anonymous
 4 years ago
if y= 5x/x^3 4, then dy/dx =?
anonymous
 4 years ago
if y= 5x/x^3 4, then dy/dx =?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y=5x/x^3 4 y=5/x^24 y=5*[x^(2)}4 dy/dx=5*(2) [ x^(21)]0 dy/dx=10*x^(3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why in the second step the exponent became 2...did you subtract

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.0is your expression on right hand side 5x/(x^3 4) ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well i thought 4 is not included , and acc I have diffrenctd , whereas had it been with x^3 , ans would have been diff

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now if its included , quotient rule has to be applied

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in the denominator it is....x^(3)  4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops dn my ans is wrong ! wait I'll explain you this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[ f(x) = \frac {5x}{x^3 4} \implies f'(x) = \frac{(x^3 4)\times 5 5x \times(3x)}{(x^3 4)^2} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0quotient rule : {(dy/dx numerator)*denominator[(dy/dx denominator)*numerator]} / denominator^2 try solving with this , if you get stuck , letme know ! btw FFM has done a great job already , so you wont find any pro ! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0fool for math, why isnt it 3x^2 in the numerator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lol, because It was a typo.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[ f(x) = \frac {5x}{x^3 4} \implies f'(x) \] \[= \frac{(x^3 4)\times 5 5x \times(3x^2)}{(x^3 4)^2} = \frac{10 \left(2+x^3\right)}{\left(4+x^3\right)^2} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do check my algebra, don't ever forget that I am a Fool ;) :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0looks right...10x^3  20/ (x^3  4)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea thats right ! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wow! Congratz too me :D Yay!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just strict to the formula , and you ll never be wrong !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops ! typing error , stick ! :p

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol, it happens to nonfools too :D
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