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Jinnie

if y= 5x/x^3 -4, then dy/dx =?

  • 2 years ago
  • 2 years ago

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  1. anjali_pant
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    y=5x/x^3 -4 y=5/x^2-4 y=5*[x^(-2)}-4 dy/dx=5*(-2) [ x^(-2-1)]-0 dy/dx=-10*x^(-3)

    • 2 years ago
  2. Jinnie
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    why in the second step the exponent became 2...did you subtract

    • 2 years ago
  3. anjali_pant
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    dividing x by x^3

    • 2 years ago
  4. Jinnie
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    ok thanks

    • 2 years ago
  5. anjali_pant
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    welcum ! :-)

    • 2 years ago
  6. experimentX
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    is your expression on right hand side 5x/(x^3 -4) ??

    • 2 years ago
  7. Jinnie
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    yea

    • 2 years ago
  8. anjali_pant
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    well i thought 4 is not included , and acc I have diffrenctd , whereas had it been with x^3 , ans would have been diff

    • 2 years ago
  9. anjali_pant
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    now if its included , quotient rule has to be applied

    • 2 years ago
  10. Jinnie
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    wait

    • 2 years ago
  11. Jinnie
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    in the denominator it is....x^(3) - 4

    • 2 years ago
  12. anjali_pant
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    oops dn my ans is wrong ! wait I'll explain you this one

    • 2 years ago
  13. FoolForMath
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    \[ f(x) = \frac {5x}{x^3 -4} \implies f'(x) = \frac{(x^3 -4)\times 5 -5x \times(3x)}{(x^3 -4)^2} \]

    • 2 years ago
  14. anjali_pant
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    quotient rule : {(dy/dx numerator)*denominator-[(dy/dx denominator)*numerator]} / denominator^2 try solving with this , if you get stuck , letme know ! btw FFM has done a great job already , so you wont find any pro ! :-)

    • 2 years ago
  15. Jinnie
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    fool for math, why isnt it 3x^2 in the numerator

    • 2 years ago
  16. FoolForMath
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    Lol, because It was a typo.

    • 2 years ago
  17. FoolForMath
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    \[ f(x) = \frac {5x}{x^3 -4} \implies f'(x) \] \[= \frac{(x^3 -4)\times 5 -5x \times(3x^2)}{(x^3 -4)^2} = -\frac{10 \left(2+x^3\right)}{\left(-4+x^3\right)^2} \]

    • 2 years ago
  18. FoolForMath
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    Do check my algebra, don't ever forget that I am a Fool ;) :P

    • 2 years ago
  19. Jinnie
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    lol

    • 2 years ago
  20. FoolForMath
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    ;)

    • 2 years ago
  21. Jinnie
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    looks right...-10x^3 - 20/ (x^3 - 4)^2

    • 2 years ago
  22. anjali_pant
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    yea thats right ! :-)

    • 2 years ago
  23. FoolForMath
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    Wow! Congratz too me :D Yay!!!

    • 2 years ago
  24. anjali_pant
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    just strict to the formula , and you ll never be wrong !

    • 2 years ago
  25. FoolForMath
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    She mean stick.

    • 2 years ago
  26. anjali_pant
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    oops ! typing error , stick ! :p

    • 2 years ago
  27. FoolForMath
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    lol, it happens to non-fools too :D

    • 2 years ago
  28. Jinnie
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    lol

    • 2 years ago
  29. anjali_pant
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    LOL ! :D

    • 2 years ago
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