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anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.2y=5x/x^3 4 y=5/x^24 y=5*[x^(2)}4 dy/dx=5*(2) [ x^(21)]0 dy/dx=10*x^(3)

Jinnie
 2 years ago
Best ResponseYou've already chosen the best response.0why in the second step the exponent became 2...did you subtract

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0is your expression on right hand side 5x/(x^3 4) ??

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.2well i thought 4 is not included , and acc I have diffrenctd , whereas had it been with x^3 , ans would have been diff

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.2now if its included , quotient rule has to be applied

Jinnie
 2 years ago
Best ResponseYou've already chosen the best response.0in the denominator it is....x^(3)  4

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.2oops dn my ans is wrong ! wait I'll explain you this one

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.6\[ f(x) = \frac {5x}{x^3 4} \implies f'(x) = \frac{(x^3 4)\times 5 5x \times(3x)}{(x^3 4)^2} \]

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.2quotient rule : {(dy/dx numerator)*denominator[(dy/dx denominator)*numerator]} / denominator^2 try solving with this , if you get stuck , letme know ! btw FFM has done a great job already , so you wont find any pro ! :)

Jinnie
 2 years ago
Best ResponseYou've already chosen the best response.0fool for math, why isnt it 3x^2 in the numerator

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.6Lol, because It was a typo.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.6\[ f(x) = \frac {5x}{x^3 4} \implies f'(x) \] \[= \frac{(x^3 4)\times 5 5x \times(3x^2)}{(x^3 4)^2} = \frac{10 \left(2+x^3\right)}{\left(4+x^3\right)^2} \]

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.6Do check my algebra, don't ever forget that I am a Fool ;) :P

Jinnie
 2 years ago
Best ResponseYou've already chosen the best response.0looks right...10x^3  20/ (x^3  4)^2

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.2yea thats right ! :)

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.6Wow! Congratz too me :D Yay!!!

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.2just strict to the formula , and you ll never be wrong !

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.2oops ! typing error , stick ! :p

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.6lol, it happens to nonfools too :D
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