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anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
y=5x/x^3 4 y=5/x^24 y=5*[x^(2)}4 dy/dx=5*(2) [ x^(21)]0 dy/dx=10*x^(3)
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
why in the second step the exponent became 2...did you subtract
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
dividing x by x^3
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
welcum ! :)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
is your expression on right hand side 5x/(x^3 4) ??
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
well i thought 4 is not included , and acc I have diffrenctd , whereas had it been with x^3 , ans would have been diff
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
now if its included , quotient rule has to be applied
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
in the denominator it is....x^(3)  4
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
oops dn my ans is wrong ! wait I'll explain you this one
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.6
\[ f(x) = \frac {5x}{x^3 4} \implies f'(x) = \frac{(x^3 4)\times 5 5x \times(3x)}{(x^3 4)^2} \]
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
quotient rule : {(dy/dx numerator)*denominator[(dy/dx denominator)*numerator]} / denominator^2 try solving with this , if you get stuck , letme know ! btw FFM has done a great job already , so you wont find any pro ! :)
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
fool for math, why isnt it 3x^2 in the numerator
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.6
Lol, because It was a typo.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.6
\[ f(x) = \frac {5x}{x^3 4} \implies f'(x) \] \[= \frac{(x^3 4)\times 5 5x \times(3x^2)}{(x^3 4)^2} = \frac{10 \left(2+x^3\right)}{\left(4+x^3\right)^2} \]
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.6
Do check my algebra, don't ever forget that I am a Fool ;) :P
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
looks right...10x^3  20/ (x^3  4)^2
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
yea thats right ! :)
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.6
Wow! Congratz too me :D Yay!!!
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
just strict to the formula , and you ll never be wrong !
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.6
She mean stick.
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
oops ! typing error , stick ! :p
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.6
lol, it happens to nonfools too :D
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.2
LOL ! :D
 2 years ago
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