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anjali_pant

  • 4 years ago

Show , lim x->0 ( sin 1/x) not equal to 0 use epsilon delta method

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  1. FoolForMath
    • 4 years ago
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    it's lies in the interval -1,1 isn't ?

  2. anjali_pant
    • 4 years ago
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    nothing like that , prove by epsilon delta , thats all i know ! :p

  3. FoolForMath
    • 4 years ago
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    LOL!! Nice :))

  4. anjali_pant
    • 4 years ago
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    LOL ! :p

  5. experimentX
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=lim+x-%3E0+%28+sin+1%2Fx%29 seems like undefined

  6. anjali_pant
    • 4 years ago
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    is the ans there at this link ?

  7. experimentX
    • 4 years ago
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    it says that limit is undefined

  8. FoolForMath
    • 4 years ago
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    it's DNE!! :D

  9. anjali_pant
    • 4 years ago
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    but is it explained ?

  10. FoolForMath
    • 4 years ago
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    Nopes.

  11. anjali_pant
    • 4 years ago
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    lol ! I also know the ans , but the prob is explanation ! :p

  12. FoolForMath
    • 4 years ago
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    This has a somewhat rigorous proof

  13. FoolForMath
    • 4 years ago
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    This is a simple way to understand: http://mathforum.org/library/drmath/view/53369.html

  14. anjali_pant
    • 4 years ago
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    really ???

  15. FoolForMath
    • 4 years ago
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    Yes really!! :D

  16. anjali_pant
    • 4 years ago
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    thnksss !!!!! :->>

  17. FoolForMath
    • 4 years ago
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    http://www.math.washington.edu/~conroy/general/sin1overx/

  18. FoolForMath
    • 4 years ago
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    Btw nice problem!

  19. anjali_pant
    • 4 years ago
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    I have many lyk these ! epsilon delta is really gettn on my nerves ! :p

  20. FoolForMath
    • 4 years ago
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    you are studying single variable or multivariate?

  21. anjali_pant
    • 4 years ago
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    both ! Actually in eco(h) , maths is subsi ! so its not core maths , but yea its maths , so bound to study ! :p

  22. FoolForMath
    • 4 years ago
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    lol, great :D :)) I wish I could help you more on epsilon delta proofs my current syllabus only requires to get the answer any how any ways ... so I tend to avoid rigorous stuffs.

  23. anjali_pant
    • 4 years ago
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    Lucky u ! :>

  24. FoolForMath
    • 4 years ago
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    lol, I have many many others things to study so not that :P

  25. eliassaab
    • 4 years ago
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    Hint if you take the sequence \[ x_n = \frac{2}{(2n+1)\pi}\] The sequence \[ x_n\] converges to zero but \[ \sin\left ( \frac 1{x_n} \right)=\pm 1\]

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