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Show , lim x->0 ( sin 1/x) not equal to 0 use epsilon delta method

Mathematics
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it's lies in the interval -1,1 isn't ?
nothing like that , prove by epsilon delta , thats all i know ! :p
LOL!! Nice :))

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Other answers:

LOL ! :p
http://www.wolframalpha.com/input/?i=lim+x-%3E0+%28+sin+1%2Fx%29 seems like undefined
is the ans there at this link ?
it says that limit is undefined
it's DNE!! :D
but is it explained ?
Nopes.
lol ! I also know the ans , but the prob is explanation ! :p
This has a somewhat rigorous proof
This is a simple way to understand:http://mathforum.org/library/drmath/view/53369.html
really ???
Yes really!! :D
thnksss !!!!! :->>
http://www.math.washington.edu/~conroy/general/sin1overx/
Btw nice problem!
I have many lyk these ! epsilon delta is really gettn on my nerves ! :p
you are studying single variable or multivariate?
both ! Actually in eco(h) , maths is subsi ! so its not core maths , but yea its maths , so bound to study ! :p
lol, great :D :)) I wish I could help you more on epsilon delta proofs my current syllabus only requires to get the answer any how any ways ... so I tend to avoid rigorous stuffs.
Lucky u ! :>
lol, I have many many others things to study so not that :P
Hint if you take the sequence \[ x_n = \frac{2}{(2n+1)\pi}\] The sequence \[ x_n\] converges to zero but \[ \sin\left ( \frac 1{x_n} \right)=\pm 1\]

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