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A mass is oscillating on a spring with a period of 1.20 s. At t = 0 the mass has zero speed and is at x = 4.85 cm. What is the magnitude of the acceleration at t = 3.30 s?

Physics
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V=0 =>X=Xmax=maggnute=A=4.85^-2 m T=1.2 sec ω=2π/Τ α=-ω^2 * Α sin(ω t + π/2) go for it
does this stand for the acceleration am trying to find α?
am getting (-4.780cm/s^2) though not sure,i have one trial left

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Other answers:

u there?
yes
is this α my acceleration?
i too \[w=2\pi f\]
and A=4.85^-2 m
α=-ω^2 * Α sin(ω t + π/2) this is my amplitude A=4.85^-2 m ? and this is my \[w=2\pi f\] and my acceleration is this α?
yes
a=4.781906 m!!!!/sec^2 that is my ans
meaning i should x=4.85cm to meters?
I am used to SI
ok so the acceleration uis the negative of the answer u just wrote,-4.781?
i suppose if given x to cm acceleretion will be acceptable to -478.1906 cm/sec^2 (yes minus)
oops! the system says it was wrong,and dat was my last trial :)
you did nt put the whole value? -478.20 should be our ans according to given values i wrote the accurate number as i am used to (sorry)

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