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V=0 =>X=Xmax=maggnute=A=4.85^-2 m
T=1.2 sec
ω=2π/Τ
α=-ω^2 * Α sin(ω t + π/2)
go for it

does this stand for the acceleration am trying to find α?

am getting (-4.780cm/s^2) though not sure,i have one trial left

u there?

yes

is this α my acceleration?

i too \[w=2\pi f\]

and A=4.85^-2 m

yes

a=4.781906 m!!!!/sec^2
that is my ans

meaning i should x=4.85cm to meters?

I am used to SI

ok so the acceleration uis the negative of the answer u just wrote,-4.781?

i suppose if given x to cm
acceleretion will be acceptable to -478.1906 cm/sec^2
(yes minus)

oops! the system says it was wrong,and dat was my last trial :)