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krypton

  • 2 years ago

A mass is oscillating on a spring with a period of 1.20 s. At t = 0 the mass has zero speed and is at x = 4.85 cm. What is the magnitude of the acceleration at t = 3.30 s?

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  1. mos1635
    • 2 years ago
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    V=0 =>X=Xmax=maggnute=A=4.85^-2 m T=1.2 sec ω=2π/Τ α=-ω^2 * Α sin(ω t + π/2) go for it

  2. krypton
    • 2 years ago
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    does this stand for the acceleration am trying to find α?

  3. krypton
    • 2 years ago
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    am getting (-4.780cm/s^2) though not sure,i have one trial left

  4. krypton
    • 2 years ago
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    u there?

  5. mos1635
    • 2 years ago
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    yes

  6. krypton
    • 2 years ago
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    is this α my acceleration?

  7. krypton
    • 2 years ago
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    i too \[w=2\pi f\]

  8. krypton
    • 2 years ago
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    and A=4.85^-2 m

  9. krypton
    • 2 years ago
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    α=-ω^2 * Α sin(ω t + π/2) this is my amplitude A=4.85^-2 m ? and this is my \[w=2\pi f\] and my acceleration is this α?

  10. mos1635
    • 2 years ago
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    yes

  11. mos1635
    • 2 years ago
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    a=4.781906 m!!!!/sec^2 that is my ans

  12. krypton
    • 2 years ago
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    meaning i should x=4.85cm to meters?

  13. mos1635
    • 2 years ago
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    I am used to SI

  14. krypton
    • 2 years ago
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    ok so the acceleration uis the negative of the answer u just wrote,-4.781?

  15. mos1635
    • 2 years ago
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    i suppose if given x to cm acceleretion will be acceptable to -478.1906 cm/sec^2 (yes minus)

  16. krypton
    • 2 years ago
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    oops! the system says it was wrong,and dat was my last trial :)

  17. mos1635
    • 2 years ago
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    you did nt put the whole value? -478.20 should be our ans according to given values i wrote the accurate number as i am used to (sorry)

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