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anonymous
 4 years ago
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anonymous
 4 years ago
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AccessDenied
 4 years ago
Best ResponseYou've already chosen the best response.0You could probably just sequentially find common denominators between the first terms of the sequence, compute the sum or difference of those numbers, and then move on to the next number carrying the number you found, repeat. e.g. 1  5/6 6/6  5/6 1/6 (1/6) + 7/12 2/12 + 7/12 9/12 and so on

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Dear santistebanc, I already know the answer, I just don't know how to do it in a faster way, that's all.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1333869325834:dw maybe i'll just use my calculator... sorry...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Set up the summation: \[1+\sum_{n=2}^{9} \frac {(1+2n)(1)^{n+1}} {(n+1)n} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0From there you can use the Alternating Series Estimation Theorem.
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