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pythagoras123 Group Title

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  1. pythagoras123 Group Title
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  2. santistebanc Group Title
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    oh you lazy

    • 2 years ago
  3. AccessDenied Group Title
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    You could probably just sequentially find common denominators between the first terms of the sequence, compute the sum or difference of those numbers, and then move on to the next number carrying the number you found, repeat. e.g. 1 - 5/6 6/6 - 5/6 1/6 (1/6) + 7/12 2/12 + 7/12 9/12 and so on

    • 2 years ago
  4. santistebanc Group Title
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    3/5

    • 2 years ago
  5. pythagoras123 Group Title
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    Dear santistebanc, I already know the answer, I just don't know how to do it in a faster way, that's all.

    • 2 years ago
  6. dpaInc Group Title
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    |dw:1333869325834:dw| maybe i'll just use my calculator... sorry...

    • 2 years ago
  7. jasonchutko Group Title
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    Set up the summation: \[1+\sum_{n=2}^{9} \frac {(1+2n)(-1)^{n+1}} {(n+1)n} \]

    • 2 years ago
  8. jasonchutko Group Title
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    From there you can use the Alternating Series Estimation Theorem.

    • 2 years ago
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