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## pythagoras123 Group Title See attachment: 2 years ago 2 years ago

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1. pythagoras123 Group Title

2. santistebanc Group Title

oh you lazy

3. AccessDenied Group Title

You could probably just sequentially find common denominators between the first terms of the sequence, compute the sum or difference of those numbers, and then move on to the next number carrying the number you found, repeat. e.g. 1 - 5/6 6/6 - 5/6 1/6 (1/6) + 7/12 2/12 + 7/12 9/12 and so on

4. santistebanc Group Title

3/5

5. pythagoras123 Group Title

Dear santistebanc, I already know the answer, I just don't know how to do it in a faster way, that's all.

6. dpaInc Group Title

|dw:1333869325834:dw| maybe i'll just use my calculator... sorry...

7. jasonchutko Group Title

Set up the summation: $1+\sum_{n=2}^{9} \frac {(1+2n)(-1)^{n+1}} {(n+1)n}$

8. jasonchutko Group Title

From there you can use the Alternating Series Estimation Theorem.