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santistebanc Group TitleBest ResponseYou've already chosen the best response.0
oh you lazy
 2 years ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.0
You could probably just sequentially find common denominators between the first terms of the sequence, compute the sum or difference of those numbers, and then move on to the next number carrying the number you found, repeat. e.g. 1  5/6 6/6  5/6 1/6 (1/6) + 7/12 2/12 + 7/12 9/12 and so on
 2 years ago

pythagoras123 Group TitleBest ResponseYou've already chosen the best response.0
Dear santistebanc, I already know the answer, I just don't know how to do it in a faster way, that's all.
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
dw:1333869325834:dw maybe i'll just use my calculator... sorry...
 2 years ago

jasonchutko Group TitleBest ResponseYou've already chosen the best response.1
Set up the summation: \[1+\sum_{n=2}^{9} \frac {(1+2n)(1)^{n+1}} {(n+1)n} \]
 2 years ago

jasonchutko Group TitleBest ResponseYou've already chosen the best response.1
From there you can use the Alternating Series Estimation Theorem.
 2 years ago
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