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pythagoras123

  • 2 years ago

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  1. pythagoras123
    • 2 years ago
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  2. santistebanc
    • 2 years ago
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    oh you lazy

  3. AccessDenied
    • 2 years ago
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    You could probably just sequentially find common denominators between the first terms of the sequence, compute the sum or difference of those numbers, and then move on to the next number carrying the number you found, repeat. e.g. 1 - 5/6 6/6 - 5/6 1/6 (1/6) + 7/12 2/12 + 7/12 9/12 and so on

  4. santistebanc
    • 2 years ago
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    3/5

  5. pythagoras123
    • 2 years ago
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    Dear santistebanc, I already know the answer, I just don't know how to do it in a faster way, that's all.

  6. dpaInc
    • 2 years ago
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    |dw:1333869325834:dw| maybe i'll just use my calculator... sorry...

  7. jasonchutko
    • 2 years ago
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    Set up the summation: \[1+\sum_{n=2}^{9} \frac {(1+2n)(-1)^{n+1}} {(n+1)n} \]

  8. jasonchutko
    • 2 years ago
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    From there you can use the Alternating Series Estimation Theorem.

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