A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
pythagoras123
 2 years ago
See attachment:
pythagoras123
 2 years ago
See attachment:

This Question is Closed

AccessDenied
 2 years ago
Best ResponseYou've already chosen the best response.0You could probably just sequentially find common denominators between the first terms of the sequence, compute the sum or difference of those numbers, and then move on to the next number carrying the number you found, repeat. e.g. 1  5/6 6/6  5/6 1/6 (1/6) + 7/12 2/12 + 7/12 9/12 and so on

pythagoras123
 2 years ago
Best ResponseYou've already chosen the best response.0Dear santistebanc, I already know the answer, I just don't know how to do it in a faster way, that's all.

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1333869325834:dw maybe i'll just use my calculator... sorry...

jasonchutko
 2 years ago
Best ResponseYou've already chosen the best response.1Set up the summation: \[1+\sum_{n=2}^{9} \frac {(1+2n)(1)^{n+1}} {(n+1)n} \]

jasonchutko
 2 years ago
Best ResponseYou've already chosen the best response.1From there you can use the Alternating Series Estimation Theorem.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.