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Peter and Jane take turns subtracting perfect squares from a given whole number and the person who subtracts the last number to get zero is the winner. If the whole number is 29, and Peter is the first player. what perfect number must he subtract in order for him to definitely win?
 2 years ago
 2 years ago
Peter and Jane take turns subtracting perfect squares from a given whole number and the person who subtracts the last number to get zero is the winner. If the whole number is 29, and Peter is the first player. what perfect number must he subtract in order for him to definitely win?
 2 years ago
 2 years ago

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experimentXBest ResponseYou've already chosen the best response.2
16 then Jane would have to subtract either 4 or 9, then jackpot for Peter
 2 years ago

pythagoras123Best ResponseYou've already chosen the best response.0
Er.. But Jane can subtract 1 and 16 also..
 2 years ago

experimentXBest ResponseYou've already chosen the best response.2
Yeah ... it seems that way.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.2
29 = 25 + 4 = 16 + 9 + 4 but there's no other way. If Jane subtracts 1 ... then it would ruin game.
 2 years ago

pythagoras123Best ResponseYou've already chosen the best response.0
29= 16+1+9+1+1+1 Jane would then draw the last one
 2 years ago

asnaseerBest ResponseYou've already chosen the best response.1
It might be best here to work in reverse. i.e. write down the outcome if, after your turn, Jane was left with 1, 2, 3, etc
 2 years ago

asnaseerBest ResponseYou've already chosen the best response.1
you can then build up to a point where you can work out your best move
 2 years ago

experimentXBest ResponseYou've already chosen the best response.2
the other way seem to be 16+4+1+1+1+1+1+1+1+1+1 and 16+1+1+1+1+1+1+1+1+1+1+1+1+1 for Peter to win, I don't think peter will win if jane does not cooperate.
 2 years ago

asnaseerBest ResponseYou've already chosen the best response.1
here is the table I worked out so far: after Peter moves, if he leaves: 1 => Jane wins 2 => Jane wins 3 => Peter wins 4 => Jane wins 5 => Jane wins 6 => Peter wins 7 => Jane wins 8 => Jane wins 9 => Jane wins 10 => Jane wins 11 => Peter wins 12 => Jane wins 13 => Peter wins so, as experimentX suggested, if Peter takes 16 first, that will leave 13 which means he would win.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.2
it seems rather like game of odd  even
 2 years ago
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