## keenaH 3 years ago y=1/3x^2-4x+6

1. wombat

Solve for x?

2. keenaH

im suposed to graph it

3. wombat

Ok. Well automatically, you can tell that it is a parabola (quadratic) right? Quadratics are more easily graphed when you have the equation in quadratic form: y=a(x-h)^2 +k So you will want to convert the above equation to this form. They you can take the vertex and y intercept from the form

4. keenaH

i forgot the step after finding the vertex and the formula you use to do it

5. wombat

The vertex is the point (h,k)

6. keenaH

im pretty sure the vertex is(6,-6)

7. keenaH

i used the formula ...x=-(b)/2(a)

8. wombat

That formula works too :) That will give you the x value that is the axis of symmetry. In the case you are doing, the vertex will be ( [-b/2a], f([-b/2a]))

9. keenaH

its so confusing

10. keenaH

i dont know what you just wrote, its like a foriegn language

11. keenaH

...

12. wombat

OH! sorry! um what I wrote represents the coordinate pair of the vertex. -b/2a is the x value. f(-b/2a) is the y value that coresponds with the above x value

13. afranklin12

i got 2.67

14. jhonyy9

- for you can solve it you need make it equal zero - so 1/3 x^2 -4x +6 =0 multiply both sides by 3 3x^2 ---- -12x +18 =0 3 x^2 -12x +18 =0 D =144 - 4*1*18 =144 -72 =72 x_1,2= (12+/- sqrt72)/2 =(12+/- sqrt(9*4*2))/2 =(12+/- 6sqrt2)/2 = =2(6+/-3sqrt2)/2 =6+/-3sqrt2 x_1,2=6+/-3sqrt2