A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1i spose we would nee to generate the power series for it first

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1\[[ln\frac{1}{1+2x}]'=\frac{1/(1+2x)'}{1/(1+2x)}\] \[[ln\frac{1}{1+2x}]'=\frac{2/(1+2x)^2}{1/(1+2x)}\] \[[ln\frac{1}{1+2x}]'=\frac{2/(1+2x)}{1/1}\to\ \frac{2}{1+2x}\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1lol ln(1+2x) = 2/(1+2x)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.12+4x8x^2+16x^332x^4+64x^5 ...  1+2x ) 2 (24x) 4x (4x+8x^2) 8x^2 (8x^216x^3)

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1somewhere i had seen something like this integration dln(1+2x)/dx and expand it as power series.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1soo, a relevant power series would be:\[ln(\frac{1}{1+2x})=\int\sum (1)^{n+1}\ 2^{2n}x^{n}dx\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1\[ln(\frac{1}{1+2x})=\sum_{0}^{inf}\frac{(1)^{n+1}}{n+1}x^{n+1}\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1\[ln(\frac{1}{1+2x})=\sum_{0}^{inf}\frac{(1)^{n+1}2^{n+1}}{n+1}x^{n+1}\] \[lim\frac{(1)^{n+1}2^{n+1}x^{n+1}}{n+1}\frac{n}{(1)^{n}2^{n}x^{n}}\] \[lim\frac{2x}{n+1}\frac{n}{1}\] \[xlim\frac{2n}{n+1} = 2\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1prolly shoulda taken the  with the x :)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1all non  ns should be vacated \[2x\ lim\frac{n}{n+1}=2x\] \[2x<1;\ x<\frac{1}{2}\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.