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anonymous
 4 years ago
Find the derivative of the function y = sin^[1](2x+1)
anonymous
 4 years ago
Find the derivative of the function y = sin^[1](2x+1)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got 2/sqrt(1(2x+1)^2) but apparently that ain't right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did you try solving out the (2x+1)^2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1333934423544:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0expand the radicand and factor out the 4 to get the 2's to cancel... the you'll get y'=1/sqrt(x^2x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0uh.. no...? (2x+1)^2 is 4x^2 + 4x + 1. right. so how does that work.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what about 2sin^2(2x+1)*cos(2x+1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my trig is no good man just show me the way any way just show me so i get it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0didnt use trig. just differentiation. treat it as (sin(2x+1))^1 . bring down the 1, raise whole thing to 2. thats one part of the answer. Then multiply that by the derivative of the inside. The inside (sin(2x+1)) has a derivative of cos(2x+1). Thats the second part. The last part is the derivative of the inside of that. derivative of 2x+1 is 2. Theres the three parts. Multiply them all together. better?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well ok so it's 2 * 1/sin(2x+1)^2 * cos(2x+1)... so it's 2cos(2x+1)/sin(2x+1)^2..... soooooo.........

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do i have that right so far? and then what?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats it i believe. is it not right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no dpalnc had it it's y'=1/sqrt(x^2x) in the textbook

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, http://www.wolframalpha.com/input/?i=derivative+of++y+%3D+sin%5E1%282x%2B1%29 i just looked it up. They use trig substitution and turn it into variables. look at the steps.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what. it just gives me the same answer i got. where do i go from there.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it doesn't bring you to the fluttering end solution that it shows it just brings me to 2/sqrt(1(2x+1)^2 which is what i got anyway

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0arccos x just means the inverse cosine function right like cos^1 (x) ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1333946189893:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thanks but that last q was unrelated

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0take out the 4... so it will be 2 outside.... the radical...
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