Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find the derivative of the function y = sin^[-1](2x+1)

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

i got 2/sqrt(1-(2x+1)^2) but apparently that ain't right
did you try solving out the (2x+1)^2?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

expand the radicand and factor out the 4 to get the 2's to cancel... the you'll get y'=1/sqrt(-x^2-x)
uh.. no...? (2x+1)^2 is 4x^2 + 4x + 1. right. so how does that work.
what about -2sin^-2(2x+1)*cos(2x+1)
my trig is no good man just show me the way any way just show me so i get it
didnt use trig. just differentiation. treat it as (sin(2x+1))^-1 . bring down the -1, raise whole thing to -2. thats one part of the answer. Then multiply that by the derivative of the inside. The inside (sin(2x+1)) has a derivative of cos(2x+1). Thats the second part. The last part is the derivative of the inside of that. derivative of 2x+1 is 2. Theres the three parts. Multiply them all together. better?
well ok so it's -2 * 1/sin(2x+1)^2 * cos(2x+1)... so it's -2cos(2x+1)/sin(2x+1)^2..... soooooo.........
do i have that right so far? and then what?
thats it i believe. is it not right?
no dpalnc had it it's y'=1/sqrt(-x^2-x) in the textbook
so.... yeah oy
okay, i just looked it up. They use trig substitution and turn it into variables. look at the steps.
what. it just gives me the same answer i got. where do i go from there.
it doesn't bring you to the fluttering end solution that it shows it just brings me to 2/sqrt(1-(2x+1)^2 which is what i got anyway
arccos x just means the inverse cosine function right like cos^-1 (x) ??
ok thanks but that last q was unrelated
take out the 4... so it will be 2 outside.... the radical...

Not the answer you are looking for?

Search for more explanations.

Ask your own question