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i got 2/sqrt(1-(2x+1)^2) but apparently that ain't right

did you try solving out the (2x+1)^2?

|dw:1333934423544:dw|

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uh.. no...? (2x+1)^2 is 4x^2 + 4x + 1. right. so how does that work.

crap

what about -2sin^-2(2x+1)*cos(2x+1)

my trig is no good man just show me the way any way just show me so i get it

do i have that right so far? and then what?

thats it i believe. is it not right?

no dpalnc had it it's y'=1/sqrt(-x^2-x) in the textbook

so.... yeah oy

what. it just gives me the same answer i got. where do i go from there.

nvm

arccos x just means the inverse cosine function right like cos^-1 (x) ??

|dw:1333946189893:dw|

ok thanks but that last q was unrelated

take out the 4... so it will be 2 outside.... the radical...

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