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\[\left( A-\lambda I \right)x=0\]lamda is the eigenvalue, x is the eigenvector

Did you try to plug into exraven's formula to find the eigenvectors

i thought it's lambdaI-A, not A-lambdaI

o if i just have to find x, i should be able to...

\[(A-\lambda_n \cdot I)x=0\]
For \[\lambda_1=-4\]
|dw:1333932816786:dw|

For \[\lambda_2=-5\]
|dw:1333932896865:dw|