## anonymous 4 years ago how do i find the eigenvector?

1. anonymous

$\left( A-\lambda I \right)x=0$lamda is the eigenvalue, x is the eigenvector

2. anonymous

i was able to find the eigenvalue $\left[\begin{matrix}-6 & 1 \\ -2 & -3\end{matrix}\right]$ to be $\lambda _{1}=-4, \lambda _{2}=-5$ now what's the next step?

3. myininaya

@nightshade please don't post off-topic answers. @exraven and elica85 we want x to not be the zero vector also

4. myininaya

Did you try to plug into exraven's formula to find the eigenvectors

5. anonymous

i thought it's lambdaI-A, not A-lambdaI

6. anonymous

idk what i'm doing, my school doesn't require us to take linear algebra to take diff eq so i'm suppose to know what to do but i don't

7. anonymous

o if i just have to find x, i should be able to...

8. myininaya

$(A-\lambda_n \cdot I)x=0$ For $\lambda_1=-4$ |dw:1333932816786:dw|

9. myininaya

For $\lambda_2=-5$ |dw:1333932896865:dw|