## elica85 Group Title how do i find the eigenvector? 2 years ago 2 years ago

1. exraven Group Title

$\left( A-\lambda I \right)x=0$lamda is the eigenvalue, x is the eigenvector

2. elica85 Group Title

i was able to find the eigenvalue $\left[\begin{matrix}-6 & 1 \\ -2 & -3\end{matrix}\right]$ to be $\lambda _{1}=-4, \lambda _{2}=-5$ now what's the next step?

3. myininaya Group Title

@nightshade please don't post off-topic answers. @exraven and elica85 we want x to not be the zero vector also

4. myininaya Group Title

Did you try to plug into exraven's formula to find the eigenvectors

5. elica85 Group Title

i thought it's lambdaI-A, not A-lambdaI

6. elica85 Group Title

idk what i'm doing, my school doesn't require us to take linear algebra to take diff eq so i'm suppose to know what to do but i don't

7. elica85 Group Title

o if i just have to find x, i should be able to...

8. myininaya Group Title

$(A-\lambda_n \cdot I)x=0$ For $\lambda_1=-4$ |dw:1333932816786:dw|

9. myininaya Group Title

For $\lambda_2=-5$ |dw:1333932896865:dw|