A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
problem with integration:
http://gyazo.com/89f6c648f3cf2cf0b074b3c5ed419752
I know you're supposed to separate into partial fractions, but I get 5, 2 and 3 as the top numbers ABand C. could somebody walk me through just the separation of partial fractions?
 2 years ago
problem with integration: http://gyazo.com/89f6c648f3cf2cf0b074b3c5ed419752 I know you're supposed to separate into partial fractions, but I get 5, 2 and 3 as the top numbers ABand C. could somebody walk me through just the separation of partial fractions?

This Question is Open

myname
 2 years ago
Best ResponseYou've already chosen the best response.0First, A = 5 , B= 2, C = 1 [not 3] Then,\[\int\limits(3x^2+9x+5)/(x(x+1)^2)dx= \int\limits (5/x) ( 2/(x+1)) +( 1/(x+1)^2) dx\]Now, you can use the sum and difference rule of the integration\[\int\limits\limits(3x^2+9x+5)/(x(x+1)^2)= \int\limits\limits (5/x) dx \int\limits( 2/(x+1))dx +\int\limits( 1/(x+1)^2)dx\] Next, you can use the substitution to find the antiderivatives \[\int\limits\limits\limits(3x^2+9x+5)/(x(x+1)^2) =5\ln(x)  2\ln(x+1) + (1/x+1)\]

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{} (A/x) + \int\limits_{}^{} (B/(x+1) + \int\limits_{}^{} (C/(x+1)^2)\] w/c leads to A=5, B=2 and C=1 = 5ln x  2 ln(x+1)  (1/(x+1)) ans....
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.