Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ggrree Group Title

problem with integration: http://gyazo.com/89f6c648f3cf2cf0b074b3c5ed419752 I know you're supposed to separate into partial fractions, but I get 5, -2 and 3 as the top numbers ABand C. could somebody walk me through just the separation of partial fractions?

  • 2 years ago
  • 2 years ago

  • This Question is Open
  1. myname Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    First, A = 5 , B= -2, C = 1 [not 3] Then,\[\int\limits(3x^2+9x+5)/(x(x+1)^2)dx= \int\limits (5/x) -( 2/(x+1)) +( 1/(x+1)^2) dx\]Now, you can use the sum and difference rule of the integration\[\int\limits\limits(3x^2+9x+5)/(x(x+1)^2)= \int\limits\limits (5/x) dx -\int\limits( 2/(x+1))dx +\int\limits( 1/(x+1)^2)dx\] Next, you can use the substitution to find the antiderivatives \[\int\limits\limits\limits(3x^2+9x+5)/(x(x+1)^2) =5\ln(x) - 2\ln(x+1) + (-1/x+1)\]

    • 2 years ago
  2. mark_o. Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\int\limits_{}^{} (A/x) + \int\limits_{}^{} (B/(x+1) + \int\limits_{}^{} (C/(x+1)^2)\] w/c leads to A=5, B=-2 and C=1 = 5ln x - 2 ln(x+1) - (1/(x+1)) ans....

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.