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using matrices |dw:1333988132875:dw|

since |A"=0 can qe use KRONECKER-CAPELLI THEOREM
i did smth like |dw:1333988210313:dw|

|dw:1333988330791:dw| but latter using gauss i got |dw:1333988378631:dw|

did i do smth wrong?? |dw:1333988426922:dw|

seems like the first and the last plane are parallel.

which???? show me please

when ever two planes are parallel, they do not have solution.

first and the last.

and two planes will give you infinite solution.

a line to be exact.

wht will b the soluyions??? can u find them Experiment?

solutions****

you will have infinite solutions, substitute z from second and third.

noo..k is a costant

your solution WOULD have been in terms of k (that what i meant by infinite).

lemme think a lil bit please

says that A must have same rank as [A|b]

use google translate
http://lavica.fesb.hr/mat1/predavanja/node38.html

yes...since r(A)=2 r(Ab) must be 2 too right

A has rank 2 i guess

what language is that Experiment??? O.o

can you tell me what is [A|b] ??

r(Ab)=4-4k at least tht's wht i found

|dw:1333989679050:dw|

r u getting anything?

Nop .. I am not really quite into mathematics ... I am just experimental

hmmm.....ok...:) Thanks anyway :D I appreciate it :))

i couldn't understand what does [A|b] represent.

Ab is the matrice formed by the constants before variables and the solutions
|dw:1333990018496:dw|

not soultions sorry..they r not called solutions..I'm just not finding the right word -_-

oh .. yeah i remember doingnthat (thanks to you). let's see what can i do for any arbitrary value .

@hoblos any idea???

for k=5, we get rank 3

okay i will check this value from -1000 to 1000

no actually u get rang 3 for every k different from 1

it seems that we get rank 2 for k = -1

oh wait...did i go wrong by equaling 4-4k=2?????????? O.o...i think i shouldn't have done that

I think i understand what's going on.

LOL ... this is quite funny.

I have never heard of KRONECKER-CAPELLI THEOREM.

my google doesn't translate tht -_-

\[ x = \frac 3 2 -z \quad y = \frac 1 2
\]
z can be any number

use translate feature of chrome.

Can u show me how u got that please @eliassaab ???

write
x + y = 2 - z
-2 x + 2 y = 2 z - 2
and solve the two equations with repect to x and y

x + y = 2 - z
-x + y = z - 1
add the two equation to get y=1/2 and then find x

sorry... instead of (-2-2k) it is (-2+2k)

But Hoblos don't u get |dw:1333991218301:dw|

i got -2-2k O.o cause i tried this too

mm i cant see the whole drawing!! always different from what?

zero

u know what....take the system and try solving it urself and ignore everything i've said

it must be equals to zero in order to have solutions!

Can't we use the rank method?

for k different than 1 we dont have solutions..

@hoblos it's -1 i think

tht's wht we're doing Fool...Kronecker-capelli :P
u don't have solutions??? how??????

why would it be -1 @experimentX ??!!

Oh god! I only didn't knew the name

@FoolForMath tht makes Anxhela happy :) now start solving it....I'm going crazyyyy!!!!!!!!! :P

because when k=1, we will have two lines ... for system of three planes.

But then I am not a Russian :P So I guess I can't blame my teacher

http://en.wikipedia.org/wiki/Rouch%C3%A9%E2%80%93Capelli_theorem

lol :D

You really do not need heavy Theorems to do a rather simple problem.

i guess .. so i might have made computation mistake.