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angela210793Best ResponseYou've already chosen the best response.0
using matrices dw:1333988132875:dw
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
since A"=0 can qe use KRONECKERCAPELLI THEOREM i did smth like dw:1333988210313:dw
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
dw:1333988330791:dw but latter using gauss i got dw:1333988378631:dw
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
did i do smth wrong?? dw:1333988426922:dw
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
seems like the first and the last plane are parallel.
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
which???? show me please
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
when ever two planes are parallel, they do not have solution.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
first and the last.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
and two planes will give you infinite solution.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
a line to be exact.
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
wht will b the soluyions??? can u find them Experiment?
 2 years ago

eliassaabBest ResponseYou've already chosen the best response.2
k=1, the last equation will be 2 times the first one The solutions lie on the line of intersections of the last two plane.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
you will have infinite solutions, substitute z from second and third.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
that will be a line, and line has infinite points. even if the first and the last line were not parallel, you were going to have infinite solution, because 4 variables and 3 equations> that usually ends up that way.
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
noo..k is a costant
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
because you are free to choose any value of k, ... and for particular value of k, you will have particular solution.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
your solution WOULD have been in terms of k (that what i meant by infinite).
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
lemme think a lil bit please
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
tht's wht i did by using Kronekercapelli....but the prob is that i get 0+0+0=2 at the last equation.... maybe i am being too dumb but i am really not getting it
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
says that A must have same rank as [Ab]
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
use google translate http://lavica.fesb.hr/mat1/predavanja/node38.html
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
yes...since r(A)=2 r(Ab) must be 2 too right
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
A has rank 2 i guess
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
what language is that Experiment??? O.o
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
it has rank two ... checked from soft. Croatian ... i don't understand too. i used google to translate.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
can you tell me what is [Ab] ??
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
r(Ab)=44k at least tht's wht i found
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
dw:1333989679050:dw
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
r u getting anything?
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
Nop .. I am not really quite into mathematics ... I am just experimental
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
hmmm.....ok...:) Thanks anyway :D I appreciate it :))
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
i couldn't understand what does [Ab] represent.
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
Ab is the matrice formed by the constants before variables and the solutions dw:1333990018496:dw
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
not soultions sorry..they r not called solutions..I'm just not finding the right word _
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
oh .. yeah i remember doingnthat (thanks to you). let's see what can i do for any arbitrary value .
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
@hoblos any idea???
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
for k=5, we get rank 3
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
okay i will check this value from 1000 to 1000
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
no actually u get rang 3 for every k different from 1
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
it seems that we get rank 2 for k = 1
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
oh wait...did i go wrong by equaling 44k=2?????????? O.o...i think i shouldn't have done that
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
I think i understand what's going on.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
LOL ... this is quite funny.
 2 years ago

FoolForMathBest ResponseYou've already chosen the best response.0
I have never heard of KRONECKERCAPELLI THEOREM.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
it's amazing to know that @ffm does not know something. http://lavica.fesb.hr/mat1/predavanja/node38.html
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
my google doesn't translate tht _
 2 years ago

eliassaabBest ResponseYou've already chosen the best response.2
\[ x = \frac 3 2 z \quad y = \frac 1 2 \] z can be any number
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
use translate feature of chrome.
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
Can u show me how u got that please @eliassaab ???
 2 years ago

eliassaabBest ResponseYou've already chosen the best response.2
write x + y = 2  z 2 x + 2 y = 2 z  2 and solve the two equations with repect to x and y
 2 years ago

hoblosBest ResponseYou've already chosen the best response.0
dw:1333990759995:dw this can be reduced to dw:1333990839175:dw to find solutions.. r(A) must be same as r(AB) so 2+2k=0 > k=1 thus 2y=1 > y=1/2 x1/2 + z = 1 x+z = 3/2
 2 years ago

eliassaabBest ResponseYou've already chosen the best response.2
x + y = 2  z x + y = z  1 add the two equation to get y=1/2 and then find x
 2 years ago

hoblosBest ResponseYou've already chosen the best response.0
sorry... instead of (22k) it is (2+2k)
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
But Hoblos don't u get dw:1333991218301:dw
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
i got 22k O.o cause i tried this too
 2 years ago

hoblosBest ResponseYou've already chosen the best response.0
mm i cant see the whole drawing!! always different from what?
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
u know what....take the system and try solving it urself and ignore everything i've said
 2 years ago

hoblosBest ResponseYou've already chosen the best response.0
it must be equals to zero in order to have solutions!
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
for other values of k other than 1, we will have two parallel planes and one non parallel. means two lines. for k=1, we have first plane = last pane, so we will have one line (I think this is what the theorem is trying to tell .... I did not understand anything)
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
i think the solutions r depended on k for k=1 are the soluions tht u find wht abt for kdifferent from 1?/
 2 years ago

FoolForMathBest ResponseYou've already chosen the best response.0
Can't we use the rank method?
 2 years ago

hoblosBest ResponseYou've already chosen the best response.0
for k different than 1 we dont have solutions..
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
@hoblos it's 1 i think
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
tht's wht we're doing Fool...Kroneckercapelli :P u don't have solutions??? how??????
 2 years ago

eliassaabBest ResponseYou've already chosen the best response.2
If \[ k\ne 1 \], there is no solutions. If \[ k= 1 \], there are infinite number of solutions that I listed before,
 2 years ago

hoblosBest ResponseYou've already chosen the best response.0
why would it be 1 @experimentX ??!!
 2 years ago

FoolForMathBest ResponseYou've already chosen the best response.0
Oh god! I only didn't knew the name
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
@FoolForMath tht makes Anxhela happy :) now start solving it....I'm going crazyyyy!!!!!!!!! :P
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
because when k=1, we will have two lines ... for system of three planes.
 2 years ago

FoolForMathBest ResponseYou've already chosen the best response.0
But then I am not a Russian :P So I guess I can't blame my teacher
 2 years ago

FoolForMathBest ResponseYou've already chosen the best response.0
http://en.wikipedia.org/wiki/Rouch%C3%A9%E2%80%93Capelli_theorem
 2 years ago

hoblosBest ResponseYou've already chosen the best response.0
well.. considering the first equation and the last one.. xy+z =k *(2) 2x+2y2z=2 2x+2y2z=2k 2x+2y2z=2 so k must be 1
 2 years ago

eliassaabBest ResponseYou've already chosen the best response.2
You really do not need heavy Theorems to do a rather simple problem.
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
i guess .. so i might have made computation mistake.
 2 years ago

angela210793Best ResponseYou've already chosen the best response.0
@eliassaab this is how we solve it in my univ..... @experimentX @hoblos @FoolForMath @eliassaab thanks a lot for trying and willing to help me :) forget this question :) I'll think again and repost it :))) thanks :)
 2 years ago

experimentXBest ResponseYou've already chosen the best response.4
damn;; my mistake was computational ... LOL A = [1, 1, 1, i; 1, 1, 1, 2; 2, 2, 2, 2]; should have been 2 at the end.
 2 years ago

hoblosBest ResponseYou've already chosen the best response.0
i remembred something we used to do... when r(AB) < number of variables... we have no exact solutions.. instead we use a parameter so we take z=m this gives x= 3/2 m so the solution is (3/2 m, 1/2 , m) for any m belong to R
 2 years ago
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