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shayanreloaded

  • 2 years ago

A projectile has maximum range 200m. What is the max height attained by it?

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  1. arcticf0x
    • 2 years ago
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    Do you have the formulas for range and height?

  2. shayanreloaded
    • 2 years ago
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    is the answer 50?

  3. arcticf0x
    • 2 years ago
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    Are you simply checking it?

  4. shayanreloaded
    • 2 years ago
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    yep

  5. shayanreloaded
    • 2 years ago
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    ?

  6. arcticf0x
    • 2 years ago
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    Would you care to show your working?

  7. shayanreloaded
    • 2 years ago
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    ok max range=v^2/g=200m therefore v=sqrt(2000) subs in eq for max height (vsin$)^2/2g for $=45 degree g =10m/s^2 i get max height 50m is it correct?

  8. arcticf0x
    • 2 years ago
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    Yep, correct. Therefore, to conclude, for an ideal projectile motion, \[R\max = 4 H\]

  9. shayanreloaded
    • 2 years ago
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    thanks

  10. arcticf0x
    • 2 years ago
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    and thats Hmax.

  11. shayanreloaded
    • 2 years ago
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    noted

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