shayanreloaded
A projectile has maximum range 200m. What is the max height attained by it?



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arcticf0x
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Do you have the formulas for range and height?

shayanreloaded
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is the answer 50?

arcticf0x
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Are you simply checking it?

shayanreloaded
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yep

shayanreloaded
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?

arcticf0x
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Would you care to show your working?

shayanreloaded
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ok
max range=v^2/g=200m
therefore v=sqrt(2000)
subs in eq for max height
(vsin$)^2/2g for $=45 degree g =10m/s^2
i get
max height 50m
is it correct?

arcticf0x
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Yep, correct.
Therefore, to conclude, for an ideal projectile motion, \[R\max = 4 H\]

shayanreloaded
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thanks

arcticf0x
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and thats Hmax.

shayanreloaded
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noted