anonymous
  • anonymous
A projectile has maximum range 200m. What is the max height attained by it?
Physics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Do you have the formulas for range and height?
anonymous
  • anonymous
is the answer 50?
anonymous
  • anonymous
Are you simply checking it?

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anonymous
  • anonymous
yep
anonymous
  • anonymous
?
anonymous
  • anonymous
Would you care to show your working?
anonymous
  • anonymous
ok max range=v^2/g=200m therefore v=sqrt(2000) subs in eq for max height (vsin$)^2/2g for $=45 degree g =10m/s^2 i get max height 50m is it correct?
anonymous
  • anonymous
Yep, correct. Therefore, to conclude, for an ideal projectile motion, \[R\max = 4 H\]
anonymous
  • anonymous
thanks
anonymous
  • anonymous
and thats Hmax.
anonymous
  • anonymous
noted

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