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shayanreloaded

A projectile has maximum range 200m. What is the max height attained by it?

  • 2 years ago
  • 2 years ago

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  1. arcticf0x
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    Do you have the formulas for range and height?

    • 2 years ago
  2. shayanreloaded
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    is the answer 50?

    • 2 years ago
  3. arcticf0x
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    Are you simply checking it?

    • 2 years ago
  4. shayanreloaded
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    yep

    • 2 years ago
  5. shayanreloaded
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    ?

    • 2 years ago
  6. arcticf0x
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    Would you care to show your working?

    • 2 years ago
  7. shayanreloaded
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    ok max range=v^2/g=200m therefore v=sqrt(2000) subs in eq for max height (vsin$)^2/2g for $=45 degree g =10m/s^2 i get max height 50m is it correct?

    • 2 years ago
  8. arcticf0x
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    Yep, correct. Therefore, to conclude, for an ideal projectile motion, \[R\max = 4 H\]

    • 2 years ago
  9. shayanreloaded
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    thanks

    • 2 years ago
  10. arcticf0x
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    and thats Hmax.

    • 2 years ago
  11. shayanreloaded
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    noted

    • 2 years ago
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