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rainbow22
Group Title
Center of a circle with this equation:
y^26x8y+20=x^2
 2 years ago
 2 years ago
rainbow22 Group Title
Center of a circle with this equation: y^26x8y+20=x^2
 2 years ago
 2 years ago

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Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Get the variables on the left and the constant term on the right. complete the square twice and write the equation in the form: \[(xh)^2+(yk)^2=r^2\]
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
I did but I end up with what I believe is the wrong answer. Okay, so obviously it would be (x4)^2+(y3)^3=20
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
I am confused as to what to do with the neg.
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
What negative?
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
The neg in front of the twenty
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
y^26x8y+20=x^2 x^2 +y^26x8y+20= 0 centre = (D/2 , E/2) in the form x^2 +y^2+Dx+Ey+F= 0 Therefore centre = ( (6/2) , (8/2) ) =...... Can you do it now?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Nothing. It will be gone because you will be adding numbers to the right and the left sides.
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Ok. callisto wants to help you now. Good bye and good luck.
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
center is therefore.. (3,4) right?
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
No... the sign is not correct
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
sooo it's (3,4).
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
So basically it's still the same center as it would be without the negatives...?
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
Okay. Also, what the radius would be sqrtroot of 20.. right?
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
Sorry, but just for conformation.. It doesn't matter if there is a negative for the 'r', the center would still be the same.
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
Nope.. \[r = \sqrt { (D/2)^2 + (E/2)^2 F}\]
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
D=6, E=8 , F=20 in your case. Put the numbers into it and solve, what would you get for r?
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
squareroot of 5...
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
It should be that ...
 2 years ago

rainbow22 Group TitleBest ResponseYou've already chosen the best response.0
That.. doesn't make sense though. The radius is typically sqroot of \[(xh)^2 + (yk)^2=r^2\]
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
So, let's do the completing square once y^26x8y+20=x^2 x^2 + y^26x8y+20= 0 x^2 6x +y^28y+20 =0 (x^2 6x +9 9) +(y^28y +16 16)+20 =0 (x^2 6x +9) +(y^28y +16) 9 16 +20 =0 (x3)^2 + (y4)^2  5 =0 (x3)^2 + (y4)^2 = 5 (x3)^2 + (y4)^2 =[ sqrt (5) ]^2 r = sqrt 5 It DOES make sense
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
Here is the proof...
 2 years ago
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