Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

calyne

  • 4 years ago

Use logarithmic differentiation to find the derivative of the function y = x^x

  • This Question is Closed
  1. The_geek
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    (1+logx)x^x

  2. lgbasallote
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    y = x^x ln both sides... lny = lnx^x via reverse power rule... lny = xlnx you can use implicit differentiation now...you do know that right/

  3. calyne
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so d/dx(lny) = 1/y * y' and d/dx(xlnx) = x*1/x .....????

  4. The_geek
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it goes lyk tis logy= xlogx diff wrt to x on bth sides so on lhs its 1/y dy/dx=1+logx by product rule on rhs u get 1+logx thn dy/dx =(1+logx)y wer y is nthin bt =x^x

  5. gordonj005
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    one of my favourite derivatives. an alternative to the ones suggested above: y = e^log(x^x) = e^xlog(x) which you can differentiate using the chain rule

  6. calyne
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thx guys you just walked me through my first ever log diff problem

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy