Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Denebel Group Title

A particle moves along the x-axis so that its position at any time t> 0 is given by x(t) = t^4 - 10t^3 + 29t^2 - 36t +2. For which value of t is the speed the greatest?

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    find maxima

    • 2 years ago
  2. Denebel Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Maximum at first derivative or second?

    • 2 years ago
  3. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    o.. sorry, take derivative ... the resulting function will give you speed.

    • 2 years ago
  4. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    and the usual process of maxima

    • 2 years ago
  5. Denebel Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1334044638555:dw| The derivative graph looks something like this... where is the maximum?

    • 2 years ago
  6. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    do we have any interval of time given??

    • 2 years ago
  7. Denebel Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    No, t>0

    • 2 years ago
  8. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    it seems that we have local maximum but's that negative ... I guess at infinity then.

    • 2 years ago
  9. Denebel Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Lol, but it's multiple choice.. A. t= 1 B. t= 2 C. t= 3 D. t= 4 E. t=5

    • 2 years ago
  10. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    the distance is actually decreasing.

    • 2 years ago
  11. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    http://www.wolframalpha.com/input/?i=x%28t%29+%3D+t%5E4+-+10t%5E3+%2B+29t%5E2+-+36t+%2B2

    • 2 years ago
  12. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    http://www.wolframalpha.com/input/?i=maxima+f%28t%29+%3D+4t%5E3+-+30t%5E2+%2B+58t+-+36

    • 2 years ago
  13. Denebel Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    What does that mean for speed? Sorry, I do not understand..

    • 2 years ago
  14. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    http://www.wolframalpha.com/input/?i=maxima+d%28t%5E4+-+10t%5E3+%2B+29t%5E2+-+36t+%2B2%29%2Fdt

    • 2 years ago
  15. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    speed is rate of change of distance ... should always be positive.

    • 2 years ago
  16. Denebel Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh, ok thanks.

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.