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FoolForMathBest ResponseYou've already chosen the best response.9
n(n+1)(2n+1)/6 put n =101.
 2 years ago

apoorvkBest ResponseYou've already chosen the best response.2
sum of squares of first 'n' natural or whole nos. is \[\sum_{i=1}^{n} i^2 = n(n+1)(2n+1)/6\] so plug in n=101, calculate and enjoy!!
 2 years ago

kiddpolo43Best ResponseYou've already chosen the best response.0
n(n+1)(2n+1)/6 put n =101.
 2 years ago

apoorvkBest ResponseYou've already chosen the best response.2
what you wrote  that's for the first 'n' nos. @KIT3 , not the sum of *square of each no.*
 one year ago
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