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TaylorBaugher2

  • 2 years ago

What is the sum of all square numbers from 0 to 101?

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  1. FoolForMath
    • 2 years ago
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    n(n+1)(2n+1)/6 put n =101.

  2. apoorvk
    • 2 years ago
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    sum of squares of first 'n' natural or whole nos. is \[\sum_{i=1}^{n} i^2 = n(n+1)(2n+1)/6\] so plug in n=101, calculate and enjoy!!

  3. kiddpolo43
    • 2 years ago
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    n(n+1)(2n+1)/6 put n =101.

  4. BieberLove
    • 2 years ago
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    n=101

  5. apoorvk
    • 2 years ago
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    what you wrote - that's for the first 'n' nos. @KIT3 , not the sum of *square of each no.*

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