Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

GummyBear Group Title

A scoop of ice cream, shaped like a sphere with a diameter of 6 cm, is placed in an ice cream cone with diameter 5 cm and height 12 cm. Is the cone big enough to hold all the ice cream if it melts? Explain.

  • 2 years ago
  • 2 years ago

  • This Question is Open
  1. GummyBear Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    to hold

    • 2 years ago
  2. CeW Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Look up the volume formulas or derive them by integration. You'll get: Volume of cone is pi r(cone)^2 h(cone)/3 = pi (2.5)^2 12/3 = 25 pi (cm^3) Volume of ice cream sphere is (4/3)pi r(sphere)^3 = (4/3)*pi*3^3 = 36 pi (cm^3). Volume of ice cream is larger than that of cone so the cone is not large enough to hold the ice cream. This answer assumes the volume of the ice cream is the same frozen or melted. However ice cream always contains some air, so when melted, the volume will be less. Not enough info (like how much air is present in the ice cream in its frozen state) is given to solve if you drop that assumption.

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.