## bunnybee Group Title a circle has the equation x^2+y^2=16. find the center, radius and graph 2 years ago 2 years ago

1. bunnybee Group Title

how do I put this in standard form and general form pls?

2. Kreshnik Group Title

$\LARGE (x-0)^2+(y-0)^2=4^2$ $\LARGE Q(0,0) \quad r=4$

3. Will! Group Title

(x-a)^2 + (y-b)^2 = r^2 (a,b) = Centre r = Radius Centre is (0,0) and Radius is $\sqrt{16} = 4$

4. bunnybee Group Title

thank you ! both of you!

5. Kreshnik Group Title

Although this looks like ellipse, is a circle with radius 4 :)

6. CeW Group Title

and it is an ellipse, as well as a circle.