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bunnybee

  • 2 years ago

a circle has the equation x^2+y^2=16. find the center, radius and graph

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  1. bunnybee
    • 2 years ago
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    how do I put this in standard form and general form pls?

  2. Kreshnik
    • 2 years ago
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    \[\LARGE (x-0)^2+(y-0)^2=4^2\] \[\LARGE Q(0,0) \quad r=4\]

  3. Will!
    • 2 years ago
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    (x-a)^2 + (y-b)^2 = r^2 (a,b) = Centre r = Radius Centre is (0,0) and Radius is \[\sqrt{16} = 4\]

  4. bunnybee
    • 2 years ago
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    thank you ! both of you!

  5. Kreshnik
    • 2 years ago
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    Although this looks like ellipse, is a circle with radius 4 :)

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  6. CeW
    • 2 years ago
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    and it is an ellipse, as well as a circle.

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