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bunnybee
a circle has the equation x^2+y^2=16. find the center, radius and graph
how do I put this in standard form and general form pls?
\[\LARGE (x-0)^2+(y-0)^2=4^2\] \[\LARGE Q(0,0) \quad r=4\]
(x-a)^2 + (y-b)^2 = r^2 (a,b) = Centre r = Radius Centre is (0,0) and Radius is \[\sqrt{16} = 4\]
thank you ! both of you!
Although this looks like ellipse, is a circle with radius 4 :)
and it is an ellipse, as well as a circle.